IB Chemistry HL 1.5 Chemical Quantities Question Bank
Practise IB Chemistry HL 1.5 with evidence-led questions on moles, equations, chemical quantities and quantitative data.
- Syllabus
- First assessment 2025
- Course
- Chemistry HL
- Level
- HL
Practise IB Chemistry HL 1.5 with evidence-led questions on moles, equations, chemical quantities and quantitative data.
Phosphoryl chloride, POCl3, is a dehydrating agent.
State the balanced chemical equation for the reaction of PCl3(1) with water.
(c) (i)

Allow any combination of dots/crosses or lines to represent electron pairs. Do not penalise missing lone pairs on Cl if already penalised in (b)(i).
(ii) trigonal/triangular bipyramidal;
Do not allow ECF from Lewis structures with incorrect number of negative charge centres.
(iii) 120∘ and 90∘/180∘;
Ignore other bond angles such as 240∘ and 360∘.
Apply list principle if some correct and incorrect angles given.
The reaction between hydrogen and nitrogen monoxide is thought to proceed by the mechanism shown below.
State the equation for the overall reaction.
2NO(g)+2H2( g)→N2( g)+2H2O(g)↓
Deduce the rate expression consistent with this mechanism.
rate =k[NO]2[H2]
Explain how you would attempt to confirm this rate expression, giving the results you would expect.
test the effect «on the reaction rate» of varying each concentration «independently»
OR
test the effect of varying [NO] «on rate», whilst keeping [H2] constant AND test effect of varying [H2] «on rate», whilst keeping [NO] constant
rate proportional to [NO] 2
OR
doubling [NO] quadruples rate
rate proportional to [H2]
OR
doubling [H2] doubles rate
Remember to refer back to a (ii) for ECF.
If only one species in rate expression, third mark can be awarded for zero order discussion.
State, giving your reason, whether confirmation of the rate expression would prove that the mechanism given is correct.
no AND different mechanisms could give the same rate expression
OR
no AND mechanisms can only be disproved
OR
no AND just suggest it is consistent with the mechanism given
OR
no AND does not give information about what occurs after RDS
Suggest how the rate of this reaction could be measured experimentally.
change of pressure «at constant volume and temperature» with time
OR
change of volume «at constant pressure and temperature» with time
Marking guidance:
Accept other methods where rate can be monitored with time.
The enthalpy change for the reaction between nitrogen monoxide and hydrogen is -664 kJ and its activation energy is 63 kJ .
Sketch the potential energy profile for the overall reaction, using the axes given, indicating both the enthalpy of reaction and activation energy.


i
Accept other clear ways of indicating energy/ enthalpy changes.
This reaction is normally carried out using a catalyst. Draw a dotted line labelled "Catalysed" on the diagram above to indicate the effect of the catalyst.

(iii) Sketch and label a second Maxwell-Boltzmann energy distribution curve representing the same system but at a higher temperature, \(T_{\text {higher

ii
lower dotted curve, between same reactants and products levels, labelled "Catalysed"
3.
b
iii
second curve at a higher temperature is correctly drawn (maximum lower and to right of original)
Explain why an increase in temperature increases the rate of this reaction.

greater proportion of molecules have E >= E_a or E>E_a
OR
greater area under curve to the right of the E_a
greater frequency of collisions «between molecules»
OR
more collisions per unit time/second
Marking guidance:
Do not accept just particles have greater kinetic energy.
Do not accept just "more collisions".
Nitrous acid, HNO2, is a weak acid which can be used to make acidic buffers.
A catalyst, usually concentrated sulfuric acid, H2SO4, is used in the manufacture of this ester.
Explain the action of a catalyst.
increases rate of reaction
lowers activation energy / by providing an alternative/lower energy pathway / greater
number of particles have energy greater than activation energy
The overall reaction for the synthesis of ethyl ethanoate from ethane is:
The progress of the reaction was followed until equilibrium was reached.
Sketch a graph showing how the rates of the forward and reverse reactions change from the beginning of the reaction, until equilibrium has been reached.

shape of graph lines correct.
AND
finishing at the same rate.
top line identified as forward reaction.
AND
lower line identified as reverse reaction.
Accept straight lines from the starting points to the equilibrium rate.
Do not accept "reactants / products" or formulas for "forward / reverse"
A student attempted to confirm the value for K obtained in (d)(viii).
0.6 moles each of ethanol and ethanoic acid reacted in the presence of an acid catalyst. The volume remained constant. After 10 minutes, 0.2 moles of ethanoic acid remained in the reaction mixture.
Determine the student's experimental value of K under these conditions.
«moles of» ethanol «at equilibrium» =0.2 «moles of» ethyl ethanoate «at equilibrium» =0.4 «moles of» water «at equilibrium» =0.4
0.220.42<0.04><0.16≫4.0
Marking guidance:
Award [3] for correct final answer.
M1 can be awarded for a correct expression for M2.
Suggest a reason for the difference between the value of the equilibrium constant, K, determined from experimental values in (e)(i) and the correct value calculated for K, in (d)(viii).
If you did not obtain values for these, use 7.15 for (d)(viii) and 3.75 for (e)(i), although these are not the correct values.
«the value of K in (e)(i) is too low and» insufficient time was given for equilibrium to be
reached.
State the correct name for the value determined in e(i).
reaction quotient / Q
Two groups of students (Group A and Group B) carried out a project* on the chemistry of some group 7 elements (the halogens) and their compounds.
In the first part of the project, the two groups had a sample of iodine monochloride (a corrosive brown liquid) prepared for them by their teacher using the following reaction.
The following data were recorded.

The iodine used in the reaction was in excess. Determine the theoretical yield, in g , of ICl(l).
n(Cl_2)=(2.24/2 x 35.45=) 0.0316 / 3.16 x 10^-2( mol);
Marking guidance:
Allow answers such as 3.2 x 10^-2 / 0.032 / 3.15 x 10^-2 / 0.0315 (mol).
n(ICl)=2 x 0.0316 / 0.0632 / 6.32 x 10^-2( mol);
Allow answers such as 6.4 x 10^-2 / 0.064 / 6.3 x 10^-2 / 0.063 (mol).
m(ICl)=(0.0632 x 162.35=) 10.3( g);
Allow answers in range 10.2 to 10.4 (g).
Award [3] for correct final answer.
Calculate the percentage yield of ICl(l).
(10.38.60×100=)83.5%;
Marking guidance:
Allow answers in the range of 82.5 to 84.5\%.
The students reacted ICl(l) with CsBr(s) to form a yellow solid, CsICl2( s), as one of the products. CsICl2( s) has been found to produce very pure CsCl(s) which is used in cancer treatment.
To confirm the composition of the yellow solid, Group A determined the amount of iodine in 0.2015 g of CsICl2( s) by titrating it with 0.0500moldm−3Na2 S2O3(aq). The following data were recorded for the titration.

The overall reaction taking place during the titration is:
Calculate the amount, in mol, of iodine atoms, I , present in the sample of CsICl2( s).
(0.5×1.21×10−3)=6.05×10−4/0.000605( mol);
Marking guidance:
Accept alternate method e.g. (0.384/126.9×0.2015)=6.10×10−4/0.000610( mol).
In this project the students explored several aspects of the chemistry of the halogens. In the original preparation of ICl(1), they observed the yellow-green colour of chlorine gas, Cl2( g), reacting with solid iodine, I2( s).
Chlorine can also react with water. State the balanced chemical equation for the reaction of Cl2( g) with water.
Cl2(aq)+H2O(l)⇌HCl(aq)+HOCl(aq);
Marking guidance:
Accept →.
Accept HClO(aq).
Allow H+(aq)+Cl−(aq) for HCl(aq) and H+(aq)+−OCl(aq)/OCl−(aq)/ClO−(aq) for HOCl(aq).
Ignore state symbols.