IB Chemistry HL 3.1 Periodicity Question Bank
Practise IB Chemistry HL 3.1 with evidence-led questions on periodicity, trends, elements and properties.
- Syllabus
- First assessment 2025
- Course
- Chemistry HL
- Level
- HL
Practise IB Chemistry HL 3.1 with evidence-led questions on periodicity, trends, elements and properties.
Lithium and boron are elements in period 2 of the periodic table. Lithium occurs in group 1 (the alkali metals) and boron occurs in group 3. Isotopes exist for both elements.
Distinguish between the terms group and period.
Group: (elements in vertical) columns in periodic table and Period: (elements in horizontal) rows in periodic table; Allow elements in same group have similar chemical properties and within a period, atoms have same number of shells/energy levels (but number of electrons in valence/outer shell increases).
Marking guidance:
Allow groups distributed vertically and periods distributed horizontally / OWTTE.
Allow group number gives number of valence/outer shell electrons (for main
group elements) and period gives same number of shells/energy levels.
State the other most common ion of cobalt.
Co2+;
Marking guidance:
Accept +2, 2+, cobalt(II), II.
Explain why the complex [Co(NH3)6]Cl3 is coloured.
partially filled/incomplete d subshell/sub-level/orbitals; d orbitals split (into two sets of different energies);
(colour due to) electron transition between (split) d orbitals / d to d transitions / frequencies of visible light absorbed by electrons moving from lower to higher d levels ;
colour due to remaining frequencies / complementary colour seen; Allow wavelength as well as frequency.
Iron rusts in the presence of oxygen and water. Rusting is a redox process involving several steps that produces hydrated iron(III) oxide, Fe2O3∙nH2O, as the final product. The half-equations involved for the first step of rusting are given below.
Half-equation 1: Fe(s)→Fe2+(aq)+2e−
Half-equation 2: O2(aq)+4e−+2H2O(l)→4OH−(aq)
Identify the oxidation number of each atom in the three species in half-equation 2.

O2(aq)+4e−+2H2O(l)→4OH−(aq)
Oxidation numbers:
Award [2] for five correct and [1] for four correct.
Accept use of oxidation states 0,+1,-2,-2,+1.
Penalize once for incorrect notation, such as 2 or 2-.
State the relationship between the electron arrangement of an element and its group and period in the periodic table.
groups indicate the number of electrons in the highest energy level/outer/valence shell;
periods indicate the number of (occupied) energy levels/shells (in the atom);
Transition metals and their compounds often catalyse reactions. The catalyzed decomposition of hydrogen peroxide by CuO is an example. State two other examples of catalyzed reactions giving the transition metal or its compound acting as catalyst.
V2O5 catalyses oxidation of SO2/V2O5 is a catalyst in the Contact Process; Fe catalyses the reaction between N2 and H2/Fe is a catalyst in the Haber Process; Ni / Pd / Pt catalyses hydrogenation / manufacture of margarine / addition of hydrogen to C=C / conversion of alkenes to alkanes;
Pd / Pt is a catalyst in catalytic converters / Pd / Pt catalyzes reaction of NO2 and CO/NO2 and (unburnt) fuel/exhaust gases; Accept other correct examples.
Marking guidance:
Accept formulas or names of substances.
Iron may be extracted from iron (II) sulfide, FeS.
Justify why sulfur is classified as a non-metal by giving two of its chemical properties.
Any two of: forms acidic oxides «rather than basic oxides» forms covalent/bonds compounds «with other non-metals» forms anions «rather than cations» behaves as an oxidizing agent «rather than a reducing agent»
Marking guidance:
Award [1 max] for 2 correct nonchemical properties such as nonconductor, high ionisation energy, high electronegativity, low electron affinity if no marks for chemical properties are awarded.
Iron (II) sulfide, FeS, is ionically bonded.
Outline, in terms of their electronic structures, why the ionic radius of the sulfide ion is greater than that of the oxide ion.
«valence» electrons further from nucleus/extra electron shell/ electrons in third/3s/3p level «not second/2s/2p»
Marking guidance:
Accept 2,8 (for O2− ) and 2,8,8 (for S2− )
The first step in the extraction of iron from iron (II) sulfide is to roast it in air to form iron (III) oxide and sulfur dioxide.
Deduce the change in the oxidation state of sulfur.
+6
OR
-2 to +4
Marking guidance:
Accept "6/VI".
Accept "-II, 4/+4/IV".
Do not accept 2- to 4+.