IB Chemistry HL 3.1.5 Ion product of water (Kw) Question Bank
Practise IB Chemistry HL 3.1.5 by applying ion product of water (kw) to exam-style questions.
- Syllabus
- First assessment 2025
- Course
- Chemistry HL
- Level
- HL
Practise IB Chemistry HL 3.1.5 by applying ion product of water (kw) to exam-style questions.
Iron rusts in the presence of oxygen and water. Rusting is a redox process involving several steps that produces hydrated iron(III) oxide, Fe2O3∙nH2O, as the final product. The half-equations involved for the first step of rusting are given below.
Half-equation 1: Fe(s)→Fe2+(aq)+2e−
Half-equation 2: O2(aq)+4e−+2H2O(l)→4OH−(aq)
State a chemical equation for the partial dissociation of water into ions, including state symbols.
H2O(l)⇌H+(aq)+OH−(aq)/2H2O(l)⇌H3O+(aq)+OH−(aq);
⇌ and state symbols are necessary for the mark.
The dissociation of water into ions is reversible. State the expression for the ionic product constant of water.
Kw=[H+][OH−]/Kw=[H3O+][OH−];
The ionic product constant of water was measured at three different temperatures.

Deduce whether the ionization of water is exothermic or endothermic, giving your reason.
at higher temperatures ionization increases / at higher temperatures equilibrium shifts to right;
ionization is endothermic;
Marking guidance:
Do not allow ECF for M2.
Use the data in part (iii) to determine the pH of water at 373 K , correct to two decimal places.
5.13×10−13=[H3O+]2/[H+]2/[H3O+]/[H+]=7.16×10−7(moldm)−3);
pH=6.14 / 6.15;
Marking guidance:
Award [2] for correct final answer.