A1.2 Nucleic acids

Explore how nucleotide components, bonding, base pairing and sequence give DNA and RNA their structures, information capacity, shared code and experimental significance.

Syllabus
First assessment 2025
Topic
A1.2
Level
HL

DNA Is the Genetic Material of Living Organisms

DNA is the genetic material of all living organisms: its base sequence stores information that can be copied and inherited.

DNA occurs in chromosomes and also as smaller genomes in mitochondria and chloroplasts. Copying DNA allows cells and offspring to receive genetic information.

Apply the rule to living organisms, then handle the exception carefully: some viruses use RNA as genetic material, but viruses are not classified as living organisms.

A plant cell contains DNA in its nuclear chromosomes, mitochondria and chloroplasts; all of these DNA molecules carry heritable information.

The existence of RNA viruses does not contradict the statement about all living organisms, because viruses are not regarded as living organisms in this syllabus.

DNA as genetic material

Assessment in practice

1 marks
How it is assessed

This objective is assessed through multiple choice, commonly using State.

Command terms

State

What earns marks

Build the answer around this relationship: DNA as genetic material should be described using precise molecular vocabulary.

Representative question

Question 1

[Maximum number: 1]

The Human Genome Project completed the sequencing of the human genome by the year 2003. Which could have been a source of the entire genome in humans?

A

The contents of a red blood cell

B

The nucleus and mitochondria of a skin cell

C

The nucleus and acrosome of a sperm cell

D

The nucleus and ribosomes of any somatic cell

Build a Nucleotide from Three Parts

A nucleotide contains three components: a phosphate group, a pentose sugar and a nitrogenous base.

The sugar is the central connector: the base and phosphate are both attached to it. DNA nucleotides contain deoxyribose; RNA nucleotides contain ribose.

For the IB diagram convention, draw the phosphate as a circle, the pentose sugar as a pentagon and the base as a rectangle, with both phosphate and base connected to the sugar.

A DNA nucleotide can be represented as phosphate-circle -> deoxyribose-pentagon -> adenine-rectangle.

A nitrogenous base alone is not a nucleotide; the sugar and phosphate are also required.

Components of a nucleotide

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / Draw.

Command terms

Identify / Draw

What earns marks

Build the answer around this relationship: Components of a nucleotide should be described using precise molecular vocabulary.

Representative question

Question 1

[Maximum number: 3]

Draw a labelled diagram to show the structure of a DNA nucleotide.

Link Nucleotides through the Sugar–Phosphate Backbone

Nucleotides join when a phosphate links the sugar of one nucleotide to the sugar of the next, forming a repeating backbone.

The covalent sugar–phosphate links make the strand continuous and give it a direction. Bases project from the backbone, so their order can vary without breaking the structural chain.

When reading a strand, separate:

  • the stable sugar–phosphate backbone
  • the variable base sequence
  • the direction from one end to the other

Joining many nucleotides produces a strand with an alternating sugar–phosphate backbone and a base attached to each sugar.

The bases do not form the backbone; confusing the code with the support structure reverses the roles.

Sugar-phosphate bonding

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / Outline.

Command terms

Identify / Outline

What earns marks

Build the answer around this relationship: Sugar-phosphate bonding should be described using precise molecular vocabulary.

Watch for

Mixing up covalent sugar-phosphate bonds with hydrogen bonds between complementary bases.

Representative question

Question 1

[Maximum number: 2]

Outline the bonding between DNA nucleotides.

Base sequences and RNA roles

Base sequence to codon to amino acid pathway.

The genetic code is stored in the order of nitrogenous bases, not in the repeating sugar–phosphate backbone. DNA uses A, T, G and C; RNA uses A, U, G and C. Groups of three bases form codons, and the order of codons carries the instructions for the amino-acid sequence of a polypeptide.

RNA is a single-stranded polynucleotide formed by condensation of nucleotide monomers. Its main types have different roles in protein synthesis:

  • mRNA carries a transcript of the DNA instructions to the ribosome.
  • tRNA carries amino acids to the mRNA sequence.
  • rRNA forms part of the ribosome and provides catalytic activity for joining amino acids.

Answer chain: base sequence → genetic instructions; condensation → RNA polymer; mRNA, tRNA and rRNA → different steps in gene expression.

RNA as a polymer

Assessment in practice

4 marks
How it is assessed

This objective is assessed through structured response, commonly using Draw.

Command terms

Draw

What earns marks

Build the answer around this relationship: RNA as a polymer should be described using precise molecular vocabulary.

Representative question

Question 1

[Maximum number: 4]

Draw labelled diagrams to show the structure of RNA nucleotides and how they are linked together to form a molecule of RNA.

The DNA Double Helix Stores Two Matching Copies

DNA consists of two antiparallel polynucleotide strands whose complementary bases pair inside a double helix.

Hydrogen bonding between paired bases holds the strands together, while the sugar–phosphate backbones face outward. Because each base has a partner, either strand can guide construction of the other during copying. This arrangement combines stability with a built-in template.

The helix depends on three linked features:

  • complementary base pairing
  • antiparallel strand direction
  • an external sugar–phosphate backbone

If one strand reads A–G–C, the opposite strand reads T–C–G at the matching positions.

The two strands are not identical copies in sequence; they are complementary and run in opposite directions.

DNA as a double helix

Assessment in practice

1–3 marks
How it is assessed

This objective is assessed through structured response, commonly using Describe / Explain / Deduce.

Command terms

Describe / Explain / Deduce / Draw / Sketch

What earns marks

Build the answer around this relationship: DNA as a double helix should be described using precise molecular vocabulary.

Watch for

Mixing up covalent sugar-phosphate bonds with hydrogen bonds between complementary bases.

Representative question

Question 1

[Maximum number: 6]

Draw a simple labeled diagram to show the structure of a double stranded DNA molecule, comprising four nucleotides.

DNA and RNA Differ in Three Useful Ways

DNA and RNA differ in sugar, one base and usual strand structure, and those differences fit their different cellular roles.

DNA uses deoxyribose and thymine and is usually double-stranded, making a stable long-term store. RNA uses ribose and uracil and is usually single-stranded, making temporary messages and folded functional molecules practical.

Compare the molecules:

  • sugar: deoxyribose / ribose
  • base: thymine / uracil
  • usual form: double-stranded / single-stranded

A cell can transcribe a DNA sequence into RNA: the RNA copy uses uracil and can leave the nucleus while the DNA template remains protected.

‘RNA is always single-stranded’ is a usual structural description, not a rule that forbids every paired region.

Differences between DNA and RNA

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / State / Distinguish.

Command terms

Identify / State / Distinguish / Determine

What earns marks

Build the answer around this relationship: Differences between DNA and RNA should be described using precise molecular vocabulary.

Watch for

Listing a DNA feature as an RNA feature, especially thymine, uracil, ribose, or deoxyribose.

Representative question

Question 1

[Maximum number: 3]

Distinguish between the structures of DNA and RNA.

Complementary Pairing Makes Copying Predictable

Complementary base pairing means each base has a specific partner, allowing a strand to determine the sequence of its partner.

Hydrogen bonds give the pairs selectivity: adenine pairs with thymine in DNA (uracil in RNA), while cytosine pairs with guanine. This matching is the mechanism behind faithful copying and template reading.

Apply the pairing rule in order:

  • A ↔ T (or U in RNA)
  • C ↔ G
  • preserve the strand positions while switching to the partner base

The DNA sequence A–C–G–T has the complementary sequence T–G–C–A.

Complementary does not mean identical: the partner strand has different letters in the opposite direction.

Complementary base pairing

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / Deduce.

Command terms

Identify / Deduce

What earns marks

Build the answer around this relationship: Complementary base pairing should be described using precise molecular vocabulary.

Watch for

Mixing up covalent sugar-phosphate bonds with hydrogen bonds between complementary bases.

Representative question

Question 1

[Maximum number: 1]

Deduce the base indicated by X on the diagram.

DNA sequence diversity and genetic code

Sequence diversity and codon conservation.

DNA can vary in both length and base sequence. If a sequence has n positions and each position can contain one of four bases, there are 4ⁿ possible sequences. Even relatively short sequences can therefore store a very large number of different instructions.

Genome size and gene number vary widely between organisms, but neither is a simple measure of organismal complexity. The key idea is that variation in sequence length and order gives DNA an enormous capacity for information storage.

The genetic code is highly conserved across life: the 64 codons have nearly the same meanings in different organisms. Shared codon meanings, together with conserved genes involved in transcription, translation and ribosomes, support the inference that living organisms share a common ancestor.

“Nearly” matters because there are minor exceptions. A synonymous mutation can change a base or codon without changing the amino acid specified, so a change in DNA sequence does not always change the polypeptide sequence.

Diversity of DNA base sequences

Assessment in practice

1–4 marks
How it is assessed

This objective is assessed through structured response, commonly using Explain.

Command terms

Explain

What earns marks

Build the answer around this relationship: Diversity of DNA base sequences should be described using precise molecular vocabulary.

Representative question

Question 1

[Maximum number: 4]

Explain the diversity of possible base sequences in nucleic acids.

Conservation of genetic code

Assessment in practice

1 marks
How it is assessed

This objective is assessed through multiple choice, commonly using Explain.

Command terms

Explain

What earns marks

Exam questions often connect this idea to biotechnology or evolution.

Representative question

Question 1

[Maximum number: 1]

Some yeast genes can be replaced by human genes that then continue to produce the same human proteins in the yeast cells. Which statement helps to explain this evidence?

A

The DNA of yeast and humans is identical.

B

Yeast and humans have the same number of chromosomes.

C

The genetic code is universal.

D

Yeast and humans are both eukaryotes.

Retrieve The Core Rules

The core chain is: nucleotides have three parts; condensation builds the sugar-phosphate backbone; base order stores information; complementary pairing lets DNA copy and express that information.

  • Nucleotide parts: phosphate, pentose sugar, nitrogenous base.
  • Polymer rule: condensation forms a sugar-phosphate backbone.
  • Code rule: base order stores information and triplet codons specify amino acids.
  • Pairing rule: A-T or A-U, and C-G, enables replication and gene expression.
  • DNA/RNA contrast: DNA uses deoxyribose/T and is usually double-stranded; RNA uses ribose/U and is usually single-stranded.

Read Nucleic-Acid Direction from 5′ to 3′

HL only

Nucleic-acid strands have direction because the sugar-phosphate backbone links the 5' carbon of one nucleotide toward the 3' carbon of the next.

During replication and transcription, a new nucleic-acid strand is synthesized 5' to 3' while its template is read 3' to 5'. During translation, the ribosome reads mRNA codons in the 5' to 3' direction.

For any strand, label both ends, keep complementary DNA strands antiparallel, and write the direction before applying base pairing.

A DNA template written 3'-A-G-C-5' directs a new strand written 5'-T-C-G-3'.

Reversing only the 5' and 3' labels changes the sequence interpretation; direction is part of the strand's identity.

Directionality of RNA and DNA

HL only

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / State.

Command terms

Identify / State

What earns marks

Build the answer around this relationship: Directionality of RNA and DNA should be described using precise molecular vocabulary.

Representative question

Question 1

[Maximum number: 1]

Identify the terminal indicated by Y on the diagram.

Purines Pair with Pyrimidines to Fit the Helix

HL only

In DNA, each base pair combines one two-ring purine with one one-ring pyrimidine, so A-T and C-G pairs have equal length and the helix keeps a consistent width.

Adenine and guanine are purines; cytosine and thymine are pyrimidines. Complementary hydrogen bonding selects A-T and C-G and helps stabilize the two strands.

Classify first, then pair: A or G (purine) must face T or C (pyrimidine); the complementary pairs are A-T and C-G.

Replacing an A-T pair with a C-G pair changes the sequence but not the helix width, because both pairs contain one purine and one pyrimidine.

A purine-purine pair would be too wide and a pyrimidine-pyrimidine pair too narrow; equal pair length does not mean any purine can form the correct hydrogen bonds with any pyrimidine.

Nucleosomes Package DNA around Histones

HL only

A nucleosome consists of DNA wrapped around a core of eight histone proteins, called a histone octamer.

Linker DNA connects neighbouring nucleosomes. An additional histone, H1, attaches to linker DNA and helps hold the packaged structure together.

Identify four parts in a model: wrapped DNA, the eight-protein histone core, linker DNA, and the additional H1 histone.

Repeated nucleosomes give chromatin a beads-on-a-string appearance: each bead is DNA around a histone octamer and each connecting segment is linker DNA.

H1 is additional to the eight core histones; do not count it as one of the histone octamer.

Structure of a nucleosome

HL only

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / State / Outline.

Command terms

Identify / State / Outline / Describe

What earns marks

Build the answer around this relationship: Structure of a nucleosome should be described using precise molecular vocabulary.

Watch for

Treating a nucleosome as DNA alone instead of a DNA-protein packaging structure.

Representative question

Question 1

[Maximum number: 4]

Outline the structure and functions of nucleosomes.

Hershey–Chase and Chargaff evidence

HL only
Experiment-result comparison.

Hershey–Chase experiment (1952)

T2 bacteriophages were prepared with either ³²P-labelled DNA or ³⁵S-labelled protein. After infection of E. coli, the ³²P signal was associated with the bacterial pellet and was found in progeny phages, whereas the ³⁵S protein label remained outside the bacteria.

Observation → conclusion: DNA entered the bacterial cells and was passed to new viruses; protein did not. Therefore DNA, rather than protein, is the genetic material in this system.

Chargaff’s data

Across DNA samples, the amount of purines equalled the amount of pyrimidines, with A = T and G = C. These results supported complementary base pairing and falsified the tetranucleotide hypothesis of a repeating, fixed base pattern.

Evidence rule: state the result first, then explain what it allows us to conclude; do not present the isotope labels as the conclusion itself.

Hershey-Chase experiment

HL only

Assessment in practice

1–3 marks
How it is assessed

This objective is assessed through structured response, commonly using Outline / Describe / Explain.

Command terms

Outline / Describe / Explain

What earns marks

Build the answer around this relationship: Hershey-Chase experiment should be described using precise molecular vocabulary.

Watch for

Remembering the experiment name without explaining what each radioactive label tracked.

Representative question

Question 1

[Maximum number: 3]

Explain how this data provides evidence that DNA is the genetic material of cells.

Chargaff's data

HL only

Assessment in practice

2 marks
How it is assessed

This objective is assessed through structured response, commonly using Explain.

Command terms

Explain

What earns marks

Build the answer around this relationship: Chargaff's data should be described using precise molecular vocabulary.

Representative question

Question 1

[Maximum number: 2]

Explain the reasons for expecting a thymine percentage of 32.4 %.

Retrieve The HL Extensions

HL only

HL adds directionality, helix geometry, DNA packaging, and classic evidence. These ideas stay separate: 5′/3′ explains strand direction; purine-pyrimidine pairing explains width; nucleosomes explain packaging; Hershey-Chase and Chargaff explain evidence for DNA and base pairing.

  • Directionality: phosphodiester bonds create 5′ and 3′ ends, and DNA strands are antiparallel.
  • Helix stability: purine-pyrimidine pairing keeps width constant and hydrogen bonds stabilize base pairs.
  • Packaging: DNA wraps around histone octamers and H1 binds linker DNA.
  • Evidence: Hershey-Chase supports DNA as genetic material; Chargaff supports complementary pairing.
  • Chargaff found purines equal pyrimidines across DNA samples.

Objective notes

15 learning objectives
A1.2.1DNA as genetic material• DNA is the genetic material of all living organisms• DNA occurs in chromosomes and also in mitochondria and chloroplasts• Some viruses use RNA, but viruses are not considered living organisms2% of analysed papers 2 papers · 2 questionsViewA1.2.2Components of a nucleotide• A nucleotide contains a phosphate group, pentose sugar, and nitrogenous base• DNA nucleotides use deoxyribose; RNA nucleotides use ribose• Bases include purines A/G and pyrimidines C/T/U3% of analysed papers 3 papers · 4 questionsViewA1.2.3Sugar-phosphate bonding• Condensation reactions link nucleotides by sugar-phosphate bonds• The sugar-phosphate backbone is a continuous covalent chain• Bases project from the backbone and carry sequence information2% of analysed papers 2 papers · 2 questionsViewA1.2.4Bases form the basis of a code• Genetic information lies in the order of nitrogenous bases• DNA uses A, T, G, C; RNA uses A, U, G, C• Triplet codons specify amino acids in protein synthesis0% of analysed papers ViewA1.2.5RNA as a polymer• RNA is a single-stranded polynucleotide formed by condensation• RNA contains ribose and the bases A, U, G, and C• mRNA, tRNA, and rRNA have different roles in protein synthesis1% of analysed papers 1 paper · 1 questionViewA1.2.6DNA as a double helix• DNA has two antiparallel polynucleotide strands in a double helix• Complementary bases pair by hydrogen bonding: A-T and G-C• Draw bases attached to sugars, not phosphates12% of analysed papers 14 papers · 14 questionsViewA1.2.7Differences between DNA and RNA• DNA is usually double-stranded; RNA is usually single-stranded• DNA uses deoxyribose and thymine; RNA uses ribose and uracil• RNA molecules are usually much shorter than DNA molecules4% of analysed papers 4 papers · 4 questionsViewA1.2.8Complementary base pairing• A pairs with T in DNA and U in RNA; C pairs with G• Complementary base pairing enables accurate DNA replication• It also enables transcription and translation in gene expression3% of analysed papers 3 papers · 3 questionsViewA1.2.9Diversity of DNA base sequences• DNA can vary in length and in base sequence• Genome size and gene number vary widely between organisms• Base-sequence diversity gives DNA enormous information-storage capacity1% of analysed papers 1 paper · 1 questionViewA1.2.10Conservation of genetic code• The 64 codons have nearly the same meanings across life• Conserved genes for transcription, translation, and ribosomes support common ancestry• Synonymous mutations can preserve amino acid sequences5% of analysed papers 6 papers · 6 questionsViewA1.2.11(HL)—Directionality of RNA and DNA• 3'-5' phosphodiester bonds create 5' and 3' strand ends• DNA strands are antiparallel: one 5' to 3', the other 3' to 5'• RNA is synthesized and translated in the 5' to 3' direction2% of analysed papers 2 papers · 2 questionsViewA1.2.12(HL)—Purine-to-pyrimidine bonding and helix stability• Purine-pyrimidine pairing keeps DNA helix width constant• A-T and C-G pairs have equal length and fit the model• Hydrogen bonding between complementary bases stabilizes DNA0% of analysed papers ViewA1.2.13(HL)—Structure of a nucleosome• DNA wraps nearly twice around an octamer of histone proteins• H1 histone binds linker DNA to the histone core• Nucleosomes package DNA and allow regulated access to genes11% of analysed papers 13 papers · 15 questionsViewA1.2.14(HL)—Hershey-Chase experiment• Hershey-Chase used bacteriophages labelled with ³²P in DNA or ³⁵S in protein• ³²P-labelled DNA entered E. coli and appeared in new viruses• Results showed DNA, not protein, carries genetic information7% of analysed papers 8 papers · 8 questionsViewA1.2.15(HL)—Chargaff's data• Chargaff found purines equal pyrimidines across DNA samples• A = T and G = C supported complementary base pairing• These data falsified the tetranucleotide hypothesis0% of analysed papers View