7.5 Hardy–Weinberg Equilibrium
- Syllabus
- 2025
- Topic
- 7.5
- Level
- —
Hardy–Weinberg equilibrium predicts allele and genotype frequencies in a non-evolving population. Its conditions are an idealized null hypothesis: a reference against which observed population frequencies can be compared.
| Equilibrium condition | If the condition is violated |
|---|---|
| Large population | Genetic drift can change allele frequencies |
| No migration | Gene flow can add or remove alleles |
| No new mutations | Mutation can introduce new variation |
| Random mating | Genotype proportions can depart from random-mating expectations |
| No natural selection | Differential reproductive success can change allele frequencies |
p+q=1$p$ = frequency of allele 1; $q$ = frequency of allele 2.
p^2+2pq+q^2=1$p^2$ = expected frequency of allele-1 homozygotes; $2pq$ = expected heterozygote frequency; $q^2$ = expected frequency of allele-2 homozygotes.
Worked example for a hypothetical equilibrium population: if p = 0.70, then q = 1 − 0.70 = 0.30. Expected genotype frequencies are p² = (0.70)² = 0.49, 2pq = 2(0.70)(0.30) = 0.42, and q² = (0.30)² = 0.09. Check: 0.49 + 0.42 + 0.09 = 1.00. These are unitless proportions, equivalent to 49%, 42%, and 9%.
The equations produce expected frequencies only when Hardy–Weinberg conditions apply. A difference between observed and expected genotype frequencies does not identify the cause by itself; it shows that the equilibrium model or its assumptions should be investigated.