S1.6 - The Normal distribution
- Syllabus
- 2019
- Topic
- S1.6
- Level
- AS
A Normal distribution is a continuous, bell-shaped model that is symmetric about its mean μ. Write X∼N(μ,σ2), where σ2 is the variance and σ>0 is the standard deviation. Symmetry makes the mean, median and mode coincide, and probabilities are areas under the curve.
Z=σX−μ,Z∼N(0,1)
| Required event | Standard-Normal calculation |
|---|---|
| P(X<a) | Φ(σa−μ) |
| P(X>a) | 1−Φ(σa−μ) |
| P(a<X<b) | Φ(σb−μ)−Φ(σa−μ) |
| equal tails about μ | use symmetry: Φ(−z)=1−Φ(z) |
Here Φ(z)=P(Z≤z) is read from the cumulative Normal table or calculator. For X∼N(210,252),P(190<X<240)=Φ(1.2)−Φ(−0.8)=0.8849−0.2119=0.6730.Draw the event mentally before using the table: a right tail needs a complement, while an interval needs a difference.
For an unknown boundary or parameter, turn the stated cumulative probability into its z-value and use x=μ+zσ. If P(X<152)=0.05 and P(X<180)=0.60, then152=μ−1.6449σ,180=μ+0.2533σ.Subtracting gives σ=28/1.8982≈14.8, then μ≈176. The same method finds percentiles, quartiles and symmetric limits.
After finding a single-observation probability p, ordinary probability rules still apply. For independent observations, use products or a complement such as 1−(1−p)n. For a conditional event, divide the joint probability by the probability of the condition; the Normal table supplies the component areas, not the final conditional ratio.
Check that a symmetric bell-shaped model is plausible; marked skewness undermines a Normal model. Because the distribution is continuous, P(X=a)=0, so strict and inclusive endpoints give the same probability. S1.6 requires shape, symmetry and cumulative-table use, but not the density formula, derivations or interpolation between table entries.