An answer that makes reference to the following points:
- calculation of the \% abundance of the third isotope
(1)
- substitute equation
(1)
- calculation of the mass of the 3rd isotope
(1)
- answer to 2 SF only
(1)
Example of calculation
100-78.99-10.00=11.01(%)
100-78.99-10.00 = 11.01(\%)
24.32=100(24×78.99)+(25×10)+(y×11.01)y=11.012432−(24×78.99)−(25×10)
y=25.998
(4)