(d)(i) Method 1 - calculation of mass C, H and O (1) - calculation of moles C, H and O and Ignore SF except 1 SF for all methods Example of calculation: mass C=24/28 x 10.0=8.5714( g) mass H=4/28 x 10.0=1.4286( g) mass O=15.7−10.0=5.70( g)arrayc:c:c C &: & H 8.5714/12 &: & 1.4286/1 array: OX5⋅7 empirical formula empirical formula is C_2 H_4 O Method 2 - calculation of moles C_2 H_4 and O 1 calculation of moles C_2 H_4 and O_2 (moles C_2 H_4=10.0/28= ) 0.35714 (. moles .O_2=(15.7-10.0)/32=) 0.17813 - empirical formula M2 dependent on M1 empirical formula is C_2 H_4 O Method 3 - calculation of moles C_2 H_4 and (moles .C_2 H_4=) 10.0/28=0.35714 (2) M_r product (1) (M_r. product .=) 15.7/0.35714=43.96 - empirical formula and calculation of M_r of empirical formula (1) M2 dependent on M1 empirical formula is C_2 H_4 OX2 x 12+4 x 1+1 x 16=44