Match formulas before labels: removing H⁺ from an acid gives its conjugate base, while adding H⁺ to a base gives its conjugate acid with the charge adjusted by one.
Syllabus
First assessment 2019
Course
Chemistry YCH11
Level
A2
Exam points
Complete proton-transfer equations and label the two conjugate acid–base pairs consistently.
Obtain a conjugate base by removing one H⁺ or a conjugate acid by adding one H⁺.
Reject proposed pairs whose formulas differ by more than one proton or another atom.
- explain, with reference to the assumptions made, why there is a difference between the calculated and measured pH values - suggest why the measured pH values are higher than the calculated pH values.
An answer that makes reference to the following points:
- CH3CH2COOH2+
and
HCOO−
- HCOOH A1 and HCOO(−)B1 and CH3CH2COOHB2 and CH3CH2COOH2(+)A2
(1)
Allow COOH−
19(a)(iv)
This question assesses a student's ability to show a coherent and logically structured answer with linkages and fully-sustained reasoning.
Marks are awarded for indicative content and for how the answer is structured and shows lines of reasoning.
The following table shows how the marks should be awarded for indicative content.
Number of indicative marking points
seen in answer
Number of marks awarded for
indicative marking points
6
5-4
3-2
1
0
\end{tabular}
The following table shows how the marks should be awarded for structure and lines of reasoning.
\end{tabular}
The mark for indicative content should be added to the mark for lines of reasoning. For example, an answer with five indicative marking points that is partially structured with some linkages and lines of reasoning scores 4 marks (3 marks for indicative content and 1 mark for partial structure and some linkages and lines of reasoning).
If there are no linkages between points, the same five indicative marking points would yield an overall score of 3 marks (3 marks for indicative content and no marks for linkages).
If there is any incorrect chemistry, deduct mark(s) from the reasoning. If no reasoning mark(s) awarded, do not deduct mark(s).
Comment: Look for the indicative marking points first, then consider the mark for the structure of the answer and sustained line of reasoning.
Indicative points:
- IP1: use of [H+]=(Ka×[HA])
- IP2: use of pH=−log[H+]
- IP3: indication that [HA]equilibrium is lower than [HA]initial
- IP4: (because) dissociation (of both acids) is significant
- IP5: (calculated pH values lower than measured pH values because) [HA] is overestimated in the calculations
- IP6: (difference greatest for) CHCl2COOH (as is) stronger acid or two Cl atoms in CHCl2COOH are more electron withdrawing than one / stabilise anion more / weaken O-H bond more
If calculations shown, pH values are 2.0775 and 1.3239
Ignore [H+]=[A−]assumption is not valid Ignore [H+]>[A−]
Do not award [A−]>[H+]
Allow dissociation is not negligible Allow dissociation occurs
Do not award dissociation is negligible Do not award dissociation is complete
Do not award [H+]overestimated in calculation due to dissociation of water
Allow more dissociated for stronger Ignore strong acid for stronger acid Ignore CHCl2COOH has larger Ka / smaller pKa