Edexcel A-Level Chemistry A2 11.7 Deduce the Rate Determining Step From a Rate Equation and Vice Versa Questions

Practise Edexcel IAL Chemistry 11.7 by matching rate-law species and powers to slow elementary steps, deriving mechanisms and checking overall equations.

Syllabus
First assessment 2019
Course
Chemistry YCH11
Level
A2

Exam points

  • Reject a proposed slow step when it contains a reactant absent from the measured rate equation.
  • Derive a rate equation from the molecularity and species in a stated slow elementary step.
  • Check a mechanism by matching both its rate-determining step and summed overall equation.
  • explain why an observed rate equation cannot arise from one elementary step with improbable molecularity

Edexcel A-Level Chemistry A2 11.7 Deduce the Rate Determining Step From a Rate Equation and Vice Versa Questions question 1

[Maximum number: 1]

Bromate (V) ions, BrO3−\mathrm{BrO}_{3}^{-}, react with bromide ions, Br−\mathrm{Br}^{-}, in aqueous acid.

BrO3−+5Br−+6H+→3Br2+3H2O\mathrm{BrO}_{3}^{-}+5 \mathrm{Br}^{-}+6 \mathrm{H}^{+} \rightarrow 3 \mathrm{Br}_{2}+3 \mathrm{H}_{2} \mathrm{O}

The rate equation for the reaction is shown.

 rate =k[BrO3−1][Br−][H+]2\text { rate }=k\left[\mathrm{BrO}_{3}^{-1}\right]\left[\mathrm{Br}^{-}\right]\left[\mathrm{H}^{+}\right]^{2}

The first four steps in the reaction mechanism are shown.

Step 1BrO3−+H+→BrO3H\mathbf{1} \mathrm{BrO}_{3}^{-}+\mathrm{H}^{+} \rightarrow \mathrm{BrO}_{3} \mathrm{H}

Step 2BrO3H+H+→BrO3H2+2 \quad \mathrm{BrO}_{3} \mathrm{H}+\mathrm{H}^{+} \rightarrow \mathrm{BrO}_{3} \mathrm{H}_{2}^{+}

Step 3BrO3H2++Br−→Br2O2+H2O3 \mathrm{BrO}_{3} \mathrm{H}_{2}^{+}+\mathrm{Br}^{-} \rightarrow \mathrm{Br}_{2} \mathrm{O}_{2}+\mathrm{H}_{2} \mathrm{O}

Step 4Br2O2+Br−→BrO2−+Br24 \quad \mathrm{Br}_{2} \mathrm{O}_{2}+\mathrm{Br}^{-} \rightarrow \mathrm{BrO}_{2}^{-}+\mathrm{Br}_{2}

Which is the rate-determining step?

A

Step 1

B

Step 2

C

Step 3

D

Step 4

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