Question 1[Maximum number: 3]The work function energy of a clean metal surface is 5.5×10−19 J5.5 \times 10^{-19} \mathrm{~J}5.5×10−19 J.Electromagnetic radiation of wavelength 280 nm is incident on the metal surface. The metal is in a vacuum.Calculate:1. the photon energyphoton energy =2. the maximum speed vMAX v_{\text {MAX }}vMAX of the electrons emitted from the surface.vMAX=v_{\mathrm{MAX}}=vMAX=ms−1\mathrm{ms}^{-1}ms−1Mark as masteredShow Answer1. photon energy =hc/λ=h c / \lambda=hc/λ=(6.63×10−34×3.00×108)/(280×10−9)=7.1×10−19 J\begin{aligned} =\left(6.63 \times 10^{-34} \times 3.00 \times 10^{8}\right) /\left(280 \times 10^{-9}\right) =7.1 \times 10^{-19} \mathrm{~J} \end{aligned}=(6.63×10−34×3.00×108)/(280×10−9)=7.1×10−19 J2. electron energy =(7.1−5.5)×10−19 J=(7.1-5.5) \times 10^{-19} \mathrm{~J}=(7.1−5.5)×10−19 J1/2×9.11×10−31×v2=(7.1−5.5)×10−191 / 2 \times 9.11 \times 10^{-31} \times v^{2}=(7.1-5.5) \times 10^{-19}1/2×9.11×10−31×v2=(7.1−5.5)×10−19v=5.9×105 m s−1v=5.9 \times 10^{5} \mathrm{~m} \mathrm{~s}^{-1}v=5.9×105 m s−1Add to Test