CAIE A-Level Physics 16 Thermodynamics
Practise relating internal energy to temperature and molecular energy, calculating gas work with signs and applying the first law to heat and energy change.
- Syllabus
- 2028–2030
- Course
- Physics 9702
- Level
- A2
Practise relating internal energy to temperature and molecular energy, calculating gas work with signs and applying the first law to heat and energy change.
A sample of 0.26 m3 of an ideal gas is at pressure 2.0×105 Pa and temperature 290 K .
Determine:
the internal energy of the gas. Explain your reasoning.
internal energy =
internal energy = total KE + PE of molecules
or
PE = 0 so internal energy = total KE of molecules
B1
internal energy =1.3×1025×6.0×10−21=7.8×104 J
A1
The volume V of the gas in (b) is now varied, keeping its pressure constant.
On Fig. 3.1, sketch the variation with V of the internal energy U of the gas.

Fig. 3.1
straight line with positive gradient
B1
line passing through the origin
B1
By referring to both kinetic energy and potential energy, explain what is meant by the internal energy of an ideal gas.
total kinetic energy associated with random motion of molecules
M1
plus total potential energy (of molecules) but potential energy is zero
A1
A fixed mass of an ideal gas at a temperature of 20∘C is sealed in a cylinder by a piston, as shown in Fig. 2.1.

Fig. 2.1
The initial volume of the gas is 1.24×10−4 m3.
Thermal energy is supplied to the gas and its volume increases by 5.20×10−5 m3.
The piston is freely moving so that the gas is always at atmospheric pressure.
Atmospheric pressure is 1.01×105 Pa.
Calculate the work done by the gas.
work done by gas = J
W=pΔV
C1
=1.01×105×5.20×10−5=(+)5.25 J
A1
The gas in (b) is allowed to return to its starting temperature. The piston is now fixed in position.
Thermal energy is supplied to increase the temperature to the same final temperature as in (b).
Use the first law of thermodynamics to suggest and explain how the specific heat capacity of the gas for this situation compares with the value in (b)(iii).
no change in volume so no work is done (by the gas)
B1
(same temperature change so) same change in internal energy
B1
less thermal energy needs to be supplied so c is less
B1
A cylinder contains 5.12 mol of an ideal gas at pressure 5.60×105 Pa and volume 3.80×10−2 m3.
The average kinetic energy EK of a molecule of the gas is given by the expression
where k is the Boltzmann constant and T is the thermodynamic temperature.
The gas is heated at constant pressure so that its temperature rises by 125 K .
Calculate the increase in internal energy of the gas. Explain your working.
(for ideal gas,) change in internal energy is change in (total) kinetic energy (of molecules)
B1
ΔU=(3/2)×1.38×10−23×125×5.12×6.02×1023
C1
ΔU=7980 J
A1
Use the information in (b)(i) to calculate the external work done during the expansion of the gas.
W=pΔV
C1
W=5.60×105×(4.75−3.80)×10−2W=5320 J
A1
Use the first law of thermodynamics to determine the total thermal energy transferred to the gas in (b). Explain your reasoning.
energy = J
work done on the gas is negative or work is done by the gas
B1
increase in internal energy = thermal energy transferred to gas + work done on gas so thermal energy transferred to gas =7980-(-5320)
=13300 J
A1