CAIE A-Level Physics 14.1 Thermal Equilibrium
Practise explaining thermal-energy transfer from higher to lower temperature and identifying thermal equilibrium as equal temperature with no net transfer.
- Syllabus
- 2028–2030
- Course
- Physics 9702
- Level
- A2
Practise explaining thermal-energy transfer from higher to lower temperature and identifying thermal equilibrium as equal temperature with no net transfer.
Use the information in (i) to draw, on Fig. 1.1, a line to represent the temperature of the block, assuming no energy losses to the surroundings.
State
what may be deduced from the difference in the temperatures of two objects,
direction or rate of transfer of (thermal) energy
or (if different,) not in thermal equilibrium/energy is transferred
B1
A block of aluminium of mass 670 g is heated at a constant rate of 95 W for 6.0 minutes. The specific heat capacity of aluminium is 910Jkg−1 K−1. The initial temperature of the block is 24∘C.
In practice, there are energy losses to the surroundings. The actual variation with time t of the temperature θ of the block is shown in Fig. 1.1.

Fig. 1.1
1. sketch: straight line from (0,24) to (6,80)
2. temperature drop due to energy loss =(80−64)=16∘C
energy loss =0.670×910×(80−64)=9800J
or
energy to raise temperature to 64∘C=0.670×910×(64−24)=24400Jloss=(95×6×60)−24400=9800J
Fig. 2.1 shows a laboratory thermometer that is calibrated to measure temperature in degrees Celsius.

Fig. 2.1
The thermometer makes use of the fact that the density of mercury varies with temperature.
The thermometer is initially at 23.0∘C, as shown in Fig. 2.1. It is used to measure the temperature of an insulated beaker of water that is at 37.4∘C. The bulb of the thermometer is inserted into the water, and the water is stirred until the reading on the thermometer becomes steady.
The mass of water in the beaker is 18.7 g .
The mass of mercury in the thermometer is 6.94 g .
The specific heat capacity of water is 4.18 J g−1 K−1.
The specific heat capacity of mercury is 0.140 J g−1 K−1.
The glass of the thermometer and the beaker containing the water can be considered to have negligible heat capacity.
Calculate, to three significant figures, the final steady temperature indicated by the thermometer in the water. ∘C
Q=mcΔT
C1
evidence of realisation that Q lost by water =Q gained by mercury
C1
18.7×4.18×(37.4−T)=6.94×0.140×(T−23.0)
C1
T=37.2∘C
A1