CAIE A-Level Physics 12.2 Centripetal Acceleration
Practise relating inward acceleration and resultant force in uniform circular motion to speed, radius and the forces acting on the object.
- Syllabus
- 2028–2030
- Course
- Physics 9702
- Level
- A2
Practise relating inward acceleration and resultant force in uniform circular motion to speed, radius and the forces acting on the object.
A circular metal disc spins horizontally about a vertical axis, as shown in Fig. 1.1.

Fig. 1.1 (not to scale)
A piece of modelling clay is attached to the disc.
For the instant when the piece of modelling clay is in the position shown, draw on Fig. 1.1:
an arrow, labelled A , showing the direction of the acceleration of the modelling clay.
arrow, labelled A, pointing in NW direction
B1
The metal disc in Fig. 1.1 has a radius of 9.3 cm .
The centre of gravity of the modelling clay is 1.2 cm from the rim of the disc and moves with a speed of 0.68 ms−1.
Calculate the acceleration a of the centre of gravity of the modelling clay.
a= ms−2
a=v2/r or a=rω2
C1
a=0.682/(0.093−0.012) or (0.093−0.012)×8.42=5.7 m s−2
A1
A second piece of modelling clay is attached to the disc in the position shown in Fig. 1.2.

Fig. 1.2
The second piece of modelling clay has a larger mass than the first piece.
By placing one tick (✓) in each row, complete Table 1.1 to show how the quantities indicated compare for the two pieces of modelling clay.

Table 1.1
angular speed: same for both pieces
B1
linear speed: less for second piece than first piece
B1
acceleration: less for second piece than first piece
B1
With reference to velocity and acceleration, describe uniform circular motion.
constant speed or constant magnitude of velocity
B1
acceleration (always) perpendicular to velocity
B1
Two cars are moving around a horizontal circular track. One car follows path X and the other follows path Y , as shown in Fig. 1.1.

Fig. 1.1 (not to scale)
The radius of path X is 318 m . Path Y is parallel to, and 27 m outside, path X . Both cars have mass 790 kg . The maximum lateral (sideways) friction force F that the cars can experience without sliding is the same for both cars.
The maximum speed at which the car on path X can move around the track without sliding is 94 m s−1.
Calculate F.
F= N
F=mv2/r
or
v=rω and F=mrω2
C1
F=790×942/318=22000 N
A1
Both cars move around the track. Each car has the maximum speed at which it can move without sliding.
Complete Table 1.1, by placing one tick in each row, to indicate how the quantities indicated for the car on path Y compare with the car on path X .

Table 1.1
centripetal acceleration: same
B1
Marking guidance:
maximum speed: greater
B1
time taken for one lap of the track: greater
B1