3.3 Trigonometry
- Syllabus
- 9709–2028–2029
- Topic
- 3.3
- Level
- A2
\sec x=rac1{\cos x},\qquad \cosec x=rac1{\sin x},\qquad \cot x=rac1{ an x}=rac{\cos x}{\sin x},whereverthedenominatorisnon−zero.
| Function | Period | Range | Vertical asymptotes |
|---|---|---|---|
| secx | 2π | y≤−1 or y≥1 | cosx=0 |
| cosecx | 2π | y≤−1 or y≥1 | sinx=0 |
| cotx | π | all real y | sinx=0 |
Start with the corresponding cosine, sine or tangent graph over the required angles. Its denominator zeros become reciprocal asymptotes; where the denominator is ±1, the reciprocal is also ±1; use the denominator sign between asymptotes to choose each branch.
sec(π/3)=2 because cos(π/3)=1/2. At x=π/2, cosine is zero, so secant is undefined and has a vertical asymptote.
Reciprocal functions have no zeros: 1/f(x) cannot equal 0. cosecx is not sin−1x; inverse notation means a principal angle, not a reciprocal.
1+ an^2A=\sec^2A,\qquad 1+\cot^2A=\cosec^2A.Usethesetoexchangeareciprocalsquareforatangent/cotangentsquare.
\sin(A\pm B)=\sin A\cos B\pm\cos A\sin B,\cos(A\pm B)=\cos A\cos B\mp\sin A\sin B, an(A\pm B)=rac{ an A\pm an B}{1\mp an A an B}.
\sin2A=2\sin A\cos A,\quad \cos2A=\cos^2A-\sin^2A=1-2\sin^2A=2\cos^2A-1, an2A=rac{2 an A}{1- an^2A}.
Write asinheta+bcosheta=Rsin(heta+α) by matching Rcosα=a and Rsinα=b. Thus R=a2+b2 and choose the quadrant of α from both signs. A cosine form is equally valid when coefficient matching is adjusted.
For exact values, expand a compound angle built from known angles. For equations, rewrite to one function or R-form, use its range to decide existence, find all solutions in the stated interval, and check any denominator restrictions.
The sign in the cosine compound formula is opposite the sign between the angles. Identity manipulation does not remove excluded values introduced by dividing by sine, cosine or another expression.