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3.7 Vectors

Syllabus
9709–2028–2029
Topic
3.7
Level
A2

A vector notation records magnitude, direction and coordinate components

A vector has size and direction; in 2D or 3D write components as a column or i,j,k combination. The magnitude of (a,b,c) is √(a²+b²+c²).

Keep vectors distinct from points, which describe position relative to an origin. A unit vector has magnitude 1 and preserves direction.

The vector (3,4) has magnitude 5; its unit vector is (3/5,4/5).

The coordinates of a point and the components of a displacement are not interchangeable unless the origin and direction are specified.

Vector operations preserve geometric meaning when components are combined consistently

Add and subtract vectors componentwise, multiply by a scalar to change magnitude or reverse direction, and use the dot product a·b=|a||b|cosθ to test perpendicularity.

A zero vector has no direction; scalar multiples are parallel. Keep dimensions and coordinate order consistent in every operation.

(2,−1)+(−3,4)=(−1,3); vectors are perpendicular when their dot product is zero.

The dot product is a scalar, not a vector, and a negative scalar reverses direction rather than merely reducing length.

A position vector locates a point from a chosen origin

The position vector of P is OP, the directed vector from the origin O to P. The displacement from A to B is OB−OA, and the midpoint is the average of the two position vectors.

Choose one origin, preserve direction in subtraction, and translate geometric statements into vector equations such as a point dividing AB in a given ratio.

If OA=(2,1) and OB=(8,4), then AB=(6,3) and the midpoint has position (5,2.5).

AB is not the same as BA; reversing the order changes the sign of the displacement.

A straight-line vector equation describes every point on a path

A line through point a in direction d is r=a+λd. Different parameter values move along the same line, and a non-zero scalar multiple of d gives the same direction.

Use the position vector and direction vector separately; compare lines by solving component equations for a common point and compatible parameters.

r=(1,2)+λ(3,−1) passes through (1,2) and has direction (3,−1).

A point on a line is not itself a direction vector, and changing the parameter origin changes a but not the geometric line.

Parallel lines have proportional direction vectors, but need not meet

Two vector lines are parallel when their direction vectors are scalar multiples. They are identical only if they also share a point; otherwise they are distinct parallel lines.

Compare direction components first, then test a point from one line in the other. In 3D, skew lines are neither parallel nor intersecting.

r=(1,0)+λ(2,3) and r=(4,5)+μ(−4,−6) are parallel because directions are proportional; checking the point decides whether they coincide.

Equal gradients in a 2D graph are not enough to prove coincident lines; intercepts matter.

The scalar product tests angles and perpendicularity

For vectors a and b, a·b=|a||b|cosθ and in components a₁b₁+a₂b₂(+a₃b₃). A zero scalar product means perpendicular non-zero vectors.

Use the dot product to find an angle, a projection or a perpendicular condition. Check that the angle is the requested principal angle and that neither vector is zero.

(1,2)·(2,−1)=0, so the vectors are perpendicular; their magnitudes do not need to be equal.

The scalar product is not a vector and a negative value means an obtuse angle, not an impossible result.

Objective notes

6 learning objectives
ConceptA-Level CAIE Mathematics A2