dxdy=x˙y˙=t21−t−212
Finds first derivative.
dtd(t21−t−212)=(t21−t−21)2−2(21t−21+21t−23)
Differentiates dxdy with respect to t.
dx2d2y=dtd(t21−t−212)× dxdt=(t21−t−21)3−2(21t−21+21t−23)=−(t−1)3t+1
Applies chain rule. OE. Does not have to be simplified
for A1.
0<t<1
Accept -1<t<1. CWO.
5