dxdy=−2xsech2xtanhx+sech2x[=1−tanh2x−2xtanhx+2xtanh3x]
Differentiating using product rule
and chain rule for M1.
sech2x=0⇒2xtanhx−1=0
AG.
2(0.7)tanh(0.7)−1=−0.154<02(0.8)tanh(0.8)−1=0.062>0
Shows sign change. Must write
down values correct to at least 1dp
for B 1 .
4