Edexcel IGCSE Math B 5 Matrices Questions
Use this Matrices hub to move from matrix arithmetic into transformation matrices, image coordinates and drawing transformed shapes on grids.
- Syllabus
- First assessment 2018
- Course
- Math B 4MB1
Use this Matrices hub to move from matrix arithmetic into transformation matrices, image coordinates and drawing transformed shapes on grids.
The points with coordinates (1,2),(1,5) and (3,2) are the vertices of triangle A.
Find the matrix product M(121532)
(-2
-5
-2
1
1
3)
M1 Correct dimensions and at least 2 correct elements
A1 Correct matrix
A=(24−31),B=(540−2).
Calculate
A+B
Answer:
(78−3−1).
Marks: B1.
2A-4B
Answer:
(−16−8−610).
Marks: B2 fully correct;
B1 for 2 or 3 correct elements in a 2×2 matrix.
A=(2k2−3kk−9k+1),B=(13−5k).
The determinant of matrix A is equal to the determinant of matrix B.
Show that k is a root of the equation
2k3+5k2−28k−15=0.
detA=2k2(k+1)−(−3k)(k−9)=2k3+5k2−27k.detB=k−3(−5)=k+15.
Equating determinants:
2k3+5k2−27k=k+15.
Hence
2k3+5k2−28k−15=0.
Required result shown.
Marking notes:
The full equation including =0 must be seen.
The transformation with matrix C, where C is a 2×2 matrix, is equivalent to the transformation with matrix A followed by the transformation with matrix B.
Given that k is positive, find matrix C.
Determinant of matrix (acbd)=ad−bc.
Positive root:
k=3.
Substituting:
A=(18−9−64),B=(13−53).
Since A is followed by B,
C=BA.
Final answer:
C=(6327−26−6).
A=(24−31),B=(540−2).
Calculate
2A-4B
Answer:
(−16−8−610).
Marks: B2 fully correct;
B1 for 2 or 3 correct elements in a 2×2 matrix.
A=(2k2−3kk−9k+1),B=(13−5k).
The determinant of matrix A is equal to the determinant of matrix B.
Show that k is a root of the equation
2k3+5k2−28k−15=0.
detA=2k2(k+1)−(−3k)(k−9)=2k3+5k2−27k.detB=k−3(−5)=k+15.
Equating determinants:
2k3+5k2−27k=k+15.
Hence
2k3+5k2−28k−15=0.
Required result shown.
Marking notes:
The full equation including =0 must be seen.
The vertices of triangle A are the points with coordinates (2,2),(3,2) and (2,4).
Triangle A is transformed to triangle B under the transformation with matrix
P=(−200−2).
On the grid, draw and label triangle B.
Correct multiplication:
(−200−2)(223224)=(−4−4−6−4−4−8)
Triangle B drawn and labelled.
M1 for showing the correct multiplication in the correct order.
A2 for the correctly drawn triangle B, with -1 for each error or omission.
A=(2k2−3kk−9k+1),B=(13−5k).
The determinant of matrix A is equal to the determinant of matrix B.
The transformation with matrix C, where C is a 2×2 matrix, is equivalent to the transformation with matrix A followed by the transformation with matrix B.
Given that k is positive, find matrix C.
Determinant of matrix (acbd)=ad−bc.
Positive root:
k=3.
Substituting:
A=(18−9−64),B=(13−53).
Since A is followed by B,
C=BA.
Final answer:
C=(6327−26−6).