1 Number
- Syllabus
- 2016
- Topic
- 1
- Level
- —
When several operations appear together, their priority fixes the meaning: evaluate brackets first, then powers or roots, then multiplication and division, then addition and subtraction. Operations at the same priority are completed from left to right.
18-3(4-1)+8\div2=18-9+4=13
Work one priority level at a time and rewrite the whole expression after each step. A minus sign attached to a number is part of that number, so (−3)2=9 but −32=−(32)=−9.
Do not automatically do multiplication before division, or addition before subtraction: each pair has equal priority, so read from left to right. Enter brackets explicitly on a calculator when the expression contains them.
A prime number has exactly two positive factors, 1 and itself. Writing a positive integer as a product of primes exposes every factor and makes highest common factor (HCF) and lowest common multiple (LCM) systematic.
| Task | Prime-factor choice |
|---|---|
| HCF | take each common prime with the smaller exponent |
| LCM | take every prime present with the larger exponent |
28=2^2 imes7,\quad120=2^3 imes3 imes5[2pt]\operatorname{HCF}=2^2=4,\quad\operatorname{LCM}=2^3 imes3 imes5 imes7=840
HCF must divide both numbers; LCM must be a multiple of both. The number 1 is neither prime nor composite.
| Form | Result | Condition |
|---|---|---|
| aman | am+n | same base |
| am÷an | am−n | same non-zero base |
| (am)n | amn | multiply the indices |
| a0 | 1 | $a |
| e0$ | ||
| a−n | 1/an | $a |
| e0$ | ||
| ap/q | qap | use a real root in the stated domain |
16^{3/4}=(\sqrt[4]{16})^3=2^3=8,\qquad rac{x^5}{x^{-2}}=x^7;(x
e0)
Multiplication combines repeated factors, so indices add; division cancels factors, so indices subtract. A negative index means reciprocal, not a negative value.
Index laws combine powers only when the bases match. In particular, am+an cannot usually be replaced by one power.
A surd is an irrational root kept in exact form. Simplify it by extracting the largest square factor; only like surds can then be added or subtracted.
\sqrt{48}=\sqrt{16 imes3}=4\sqrt3,\qquad5\sqrt3+2\sqrt3=7\sqrt3
Products use ab=ab when the roots are defined. For example, (23)(36)=618=182.
Do not split addition inside a root: a+b is not generally a+b. Decimal approximations lose the exact value, so keep the surd until an approximation is requested.
Rationalising removes a surd from the denominator without changing the value. For a binomial denominator, multiply numerator and denominator by its conjugate: keep the terms but reverse the sign between them.
(a-b)(a+b)=a^2-b^2
rac{15}{\sqrt7-2} imesrac{\sqrt7+2}{\sqrt7+2}=rac{15(\sqrt7+2)}{7-4}=5(\sqrt7+2)
The conjugate is used because the middle surd terms cancel. Multiply the entire numerator and denominator, and simplify only after checking that the original denominator is non-zero.
| Set | Meaning | Examples |
|---|---|---|
| N | natural counting numbers | 1,2,3,…; follow the question's convention about 0 |
| Z | integers | …,−2,−1,0,1,2,… |
| Q | numbers expressible as p/q, $q | |
| e0∣-3,2/5,0.\overline7$ | ||
| irrational | real but not rational | 2, π |
\mathbb N\subset\mathbb Z\subset\mathbb Q\subset\mathbb R,\qquad ext{irrationals}=\mathbb R\setminus\mathbb Q
Terminating and recurring decimals are rational. Simplify an expression before classifying it: for example, 20/5=4=2 is natural, integer and rational.
A root symbol does not automatically make a number irrational: 49=7. Proofs of irrationality are not required here.
Choose units that match the quantity, write the given conversion as an equality, and multiply by a conversion factor equal to 1. For area or volume, the linear conversion factor must be squared or cubed.
| Quantity | Useful metric/SI link |
|---|---|
| length | 1extm=100extcm |
| area | 1extm2=10000extcm2 |
| volume/capacity | 1extm3=1000extL; 1extL=1000extcm3 |
| mass | 1extkg=1000extg |
| time | 1exth=3600exts |
ext{average speed}=rac{ ext{total distance}}{ ext{total time}},\qquad2.4 ext{ m}^2=24,000 ext{ cm}^2
For currency, use the rate exactly as stated. If 1extGBP=1.18extEUR, multiply pounds by 1.18 to obtain euros and divide euros by 1.18 to obtain pounds. Round money only at the requested stage.
Average speed is based on total distance and total time; it is not normally the mean of separate speeds. Two incomplete zero-mark Question Bank fragments were excluded from the evidence.
| Form | Conversion/use |
|---|---|
| fraction a/b | exact part of a whole; use common denominators for addition/subtraction |
| decimal | divide numerator by denominator; convenient for calculation |
| percentage | multiply a proportion by 100%; useful for comparison |
| ratio | compares parts in the same units; simplify by a common factor |
rac ab\divrac cd=rac ab imesrac dc\quad(c,d
e0),\qquad ext{percentage multiplier}=1\pmrac r{100}
To divide £420 in the ratio 2:3:5, total the shares: 2+3+5=10. One share is £42, so the amounts are £84, £126 and £210.
A ratio gives relative shares, not the actual total. For repeated percentage change, apply the multiplier each time; adding the percentages ignores the changed starting amount. Ratio and proportion questions use at most three parts in this syllabus.
| Accuracy | Where counting starts | Example |
|---|---|---|
| decimal places (dp) | first digit after the decimal point | 18.376 to 2 dp is 18.38 |
| significant figures (sf) | first non-zero digit | 0.004786 to 3 sf is 0.00479 |
Locate the final digit to keep, inspect the next digit, then increase the kept digit by 1 if the next digit is 5 or more. Replace omitted whole-number digits with zeros when needed to preserve place value.
Leading zeros are not significant, but zeros between non-zero digits are. Keep extra calculator digits during working and round the final answer unless the question directs otherwise.
x ext{ rounded to step }u ext{ as }r\quad\Longrightarrow\quad r-rac u2\le x<r+rac u2
Choose the combination that makes the required result largest or smallest. For positive quantities: an upper sum uses upper bounds; an upper difference uses the first upper and second lower; an upper product uses upper bounds; an upper quotient uses an upper numerator and lower denominator.
A_{\max}=(610.5)(155.5-75.5)=(610.5)(80)=48,840 ext{ cm}^2
Here 610, 155 and 76 are each correct to the nearest centimetre. The net height is a subtraction, so its upper bound uses 155.5−75.5, not 155.5−76.5.
A rounded value is not itself an upper or lower bound. State the interval first, and reconsider the extremum rule if a quantity can be negative.
a imes10^n,\qquad1\le a<10,\quad n\in\mathbb Z
Move the decimal point to make a coefficient between 1 and 10; the number of places moved gives the power of 10. Positive indices represent large place values and negative indices represent small positive place values.
| Operation | Method |
|---|---|
| multiply | multiply coefficients and add indices |
| divide | divide coefficients and subtract indices |
| add/subtract | first rewrite with the same power of 10 |
(3.6 imes10^7)(2 imes10^{-3})=7.2 imes10^4,\qquad 4 imes10^{100}+3.6 imes10^{101}=4.0 imes10^{101}
Normalise the final coefficient: 36imes105=3.6imes106 is standard form, but 36imes105 is not. Preserve units and round only when requested.