Question 1[Maximum number: 2]F is the point (1,-4), FG→=(8−3)\overrightarrow{FG}=\binom{8}{-3}FG=(−38) and GH→=(−1235)\overrightarrow{GH}=\binom{-12}{35}GH=(35−12).Findthe magnitude of vector GH→\overrightarrow{G H}GH.Mark as masteredShow Answer37M1 for (−12)2+352(-12)^2+35^2(−12)2+352 oeAdd to Test
Question 2[Maximum number: 3]Point A has coordinates ( -4,1 ) and BA→=(−5−12)\overrightarrow{B A}=\binom{-5}{-12}BA=(−12−5).EF→=3BA→\overrightarrow{E F}=3 \overrightarrow{B A}EF=3BAFind ∣EF→∣|\overrightarrow{E F}|∣EF∣.Mark as masteredShow Answer39B2 for ∣BA→∣=13|\overrightarrow{BA}|=13∣BA∣=13or M2 for 3([−]5)2+([−]12)23\sqrt{([-]5)^2+([-]12)^2}3([−]5)2+([−]12)2 oeor M1 for ([−]5)2+([−]12)2([-]5)^2+([-]12)^2([−]5)2+([−]12)2 oe or ([−]15)2+([−]36)2([-]15)^2+([-]36)^2([−]15)2+([−]36)2 oeAdd to Test
Question 3[Maximum number: 3]∣(9m40m)∣=2052\left|\begin{pmatrix}9m\\40m\end{pmatrix}\right|=\frac{205}{2}(9m40m)=2205Find the two possible values of m.m=m=\qquadm= or m=m=\qquadm=Mark as masteredShow Answer2.5 and -2.5 oeM2 for 1681m2=4202541681m^2=\frac{42025}{4}1681m2=442025 oeor M1 for (9m)2+(40m)2(9m)^2+(40m)^2(9m)2+(40m)2 oeAdd to Test