E8.3 Probability of combined events
- Syllabus
- 0580–2028–2029
- Topic
- E8.3
- Level
- Extended
A combined event joins conditions or stages. Choose a representation that lists every possible outcome once, then combine only the outcomes that satisfy the event.
| Representation | Best use | Probability method |
|---|---|---|
| sample space diagram | two stages fit rows and columns | mark favourable cells; count cells only when they are equally likely |
| two-set Venn diagram | outcomes belong to A, B, both or neither | P(A∩B) uses the overlap; P(A∪B) uses every region in A or B, counting the overlap once |
| tree diagram | outcomes occur in stages | multiply along each required path; add probabilities of alternative paths |
P(\text{one path})=\text{product of its branch probabilities},\qquad P(\text{alternative paths})=\text{sum of their path probabilities}
| Selection | What happens before the next branch? |
|---|---|
| with replacement | the selected item returns, so totals and probabilities reset |
| without replacement | the selected item stays out, so the total falls by 1 and the relevant category may also fall by 1 |
A bag has 5 green and 3 blue counters. With replacement, P(two green)=85×85=6425. Without replacement, after one green there are 4 green among 7 counters, so P(two green)=85×74=145.
On a tree diagram, write each outcome at the end of its branch and its probability beside the branch. Check that probabilities leaving the same point add to 1. In a Venn diagram, 'and' means the intersection ∩ and inclusive 'or' means the union ∪; the overlap must not be counted twice.
Do not use a fixed second-stage denominator in a without-replacement problem. Conditional probability notation P(A∣B) and its formulas belong to E8.4, not this card.