13.3 Mathematical and data-presentation skills

Syllabus
0620–2026–2027
Topic
13.3
Level

Learning objectives

Control the numerical chain in chemistry calculations

Treat every chemistry calculation as one controlled chain: express the data in compatible forms and units, choose the relationship, rearrange if necessary, substitute, calculate, then round only the final answer.

Requirement Reliable move
fraction, decimal, percentage convert to the form needed; percentage = fraction × 100%
ratio divide all terms by the same factor; preserve the order of quantities
reciprocal 1/x1/x reverses a non-zero factor or expresses an inverse relationship
standard form write a×10na\times10^n with 1a<101\leq a<10 and integer nn
equation keep units consistent, substitute known values and use inverse operations to isolate the unknown
direct proportion y=kxy=kx; doubling xx doubles yy
inverse proportion y=k/xy=k/x; doubling xx halves yy

c=nV,n=cV=0.250×0.0400=0.0100 molc=\frac{n}{V},\quad n=cV=0.250\times0.0400=0.0100\ \mathrm{mol}

Keep extra calculator digits through intermediate steps. Report the final result with decimal places or significant figures appropriate to the given data and the measurement context.

Do not round each intermediate value or substitute quantities in inconsistent units. A numerically correct calculator display is not a complete result when a unit is required.

Choose and convert measurement units

A unit must match the quantity and scale. Convert before substitution when an equation requires consistent units, and attach the unit to the final result.

Quantity Exact relationship Smaller unit → larger unit
volume 1000 cm3=1 dm31000\ \mathrm{cm^3}=1\ \mathrm{dm^3} divide by 1000
mass 1000 mg=1 g1000\ \mathrm{mg}=1\ \mathrm{g}; 1000 g=1 kg1000\ \mathrm{g}=1\ \mathrm{kg} divide by 1000 for each step
energy 1000 J=1 kJ1000\ \mathrm{J}=1\ \mathrm{kJ} divide by 1000
pressure 1000 Pa=1 kPa1000\ \mathrm{Pa}=1\ \mathrm{kPa} divide by 1000
Term Meaning used in measurement
radius / diameter centre-to-edge distance / full distance through the centre; diameter = 2 × radius
circumference distance around a circle
square / rectangle four-sided shapes used for area; a square has equal sides
diagonal line joining opposite corners
angle / curve amount of turn / a line whose direction changes

40.0 cm3=0.0400 dm340.0\ \mathrm{cm^3}=0.0400\ \mathrm{dm^3}; the conversion changes the numerical value but not the physical volume.

Cubic units are already volume units: the syllabus conversion is 1000 cm3=1 dm31000\ \mathrm{cm^3}=1\ \mathrm{dm^3}, not a factor of 1010 and not 10610^6 for this pair.

Choose and interpret graphs, charts and statistics

Choose a representation that matches the variables, then read only what its scale and range support. A graph displays a relationship; a mean combines comparable repeated values.

Task Mathematical tool Interpretation
show how one continuous variable changes with another line graph or scatter graph with best-fit line/curve direction, shape, intercept and values within the plotted range
compare separate categories suitable chart compare bar lengths or sector proportions using the labelled scale/key
estimate between measured points interpolation estimate within the evidence range
extend beyond measured points extrapolation prediction with greater uncertainty
rate of change on a straight line gradient =Δy/Δx=\Delta y/\Delta x include units from the two axes
starting value intercept value where the line crosses an axis
summarise repeats mean =Σx/n=\Sigma x/n use only values selected by the stated repeat/anomaly rule

Direct proportionality appears as a straight line through the origin: y=kxy=kx. A straight line with a non-zero intercept is linear but not directly proportional.

Interpolation and extrapolation are not equally secure. Do not claim direct proportion merely because the graph is straight, and do not average quantities that are not comparable repeats.

Record readings and tables with matched precision

The recorded value must reflect what the instrument can resolve. Read an analogue scale to the nearest half of the smallest division where required and preserve appropriate precision in the table.

Feature Required convention
analogue reading interpolate to the nearest half-smallest division where appropriate
measured value decimal places and significant figures reflect the instrument's precision
calculated value use the same number of significant figures as the least precise raw datum used in that calculation
table heading quantity or symbol followed by solidus and unit, e.g. time / s
table body numbers only; do not repeat units in each cell
repeated readings record each reading before calculating or selecting a representative value
ratio write in the order requested as x:yx:y

Values measured with the same instrument in one table column should normally show consistent decimal places, including trailing zeros that communicate the instrument's resolution.

Do not add unjustified digits to a coarse reading or remove meaningful trailing zeros. Significant figures describe precision; they do not make an inaccurate method accurate.

Construct and analyse a chemical-data graph

A graph must make the data relationship readable without distorting it: variables, units, scale, plotted points and the best-fit relationship all carry meaning.

Step Construction rule
axes independent variable on xx and dependent variable on yy, unless instructed otherwise
labels transfer quantity and unit from the table heading, e.g. time / s
scale use sensible 1, 2 or 5-based intervals and more than half the grid in both directions
points mark small crosses or encircled dots to half a smallest square
best fit draw one thin, smooth line or curve with roughly even scatter on both sides; ignore a clearly anomalous point when fitting
readings interpolate/extrapolate and read values or intercepts to half a smallest square
straight-line gradient use Δy/Δx\Delta y/\Delta x from a marked triangle whose hypotenuse spans at least half the best-fit line

Gradient units are yy-axis units divided by xx-axis units. Use two points on the best-fit line or its large gradient triangle, not necessarily two experimental points.

Do not join plotted points dot-to-dot unless instructed. A best-fit line need not pass through the origin or every point, and an anomaly remains plotted even when ignored for the fit.

Find the instantaneous gradient of a curve

For Extended candidates, the gradient of a curve at one point is the gradient of the tangent there. The tangent is a straight line with the same local direction as the curve.

Step Action
1 locate the required point on the smooth curve
2 draw a straight tangent that touches the curve at that point and follows its local direction, with roughly balanced separation on either side
3 choose two well-separated points on the tangent, not on the curve
4 draw a large gradient triangle and read the coordinate differences from the axes
5 calculate Δy/Δx\Delta y/\Delta x and attach yy-unit per xx-unit

instantaneous gradient=y2y1x2x1\text{instantaneous gradient}=\frac{y_2-y_1}{x_2-x_1}

A steeper tangent has a larger gradient magnitude. A horizontal tangent has gradient zero; a downward tangent gives a negative gradient with the usual axis directions.

Do not calculate between two points on the curve: that gives an average gradient over an interval. The tangent must be drawn at the specified point before the triangle is chosen.