CAIE IGCSE Additional Math 7 straight-line graphs
Use this Straight-line Graphs hub to move from line equations and gradients into perpendicular lines, midpoints, lengths and bisectors.
- Syllabus
- 2028–2030
- Course
- Additional Mathematics 0606
Use this Straight-line Graphs hub to move from line equations and gradients into perpendicular lines, midpoints, lengths and bisectors.
A straight line passes through the points (4,23) and (-8,29). Find the point of intersection, P, of this line with the line y=2x+5.
y=−21x+25 isw
B3.
M1 for m=−8−429−23 oe or −21, and M1 FT for x−4y−23= their −21 oe, or y= their −21x+c and 23=−21×4+c oe.
OR M1 for solving 23=4m+c, 29=-8m+c for m=−21 or c=25, and M1 FT for correctly using their m or their c to find c or m.
Solves their linear equation simultaneously with y=2x+5 to find x or y. M1: FT their y=−21x+25 oe.
(8,21). A1.
Find the distance of P from the origin.
82+212 oe
M1: FT their (8,21).
505 isw, or 22.5, or 22.47[22…] rot to 2 or more dp. A1.
The coordinates of points A and B are (-5,6) and (4,-6) respectively. The point C lies on the line AB, between A and B, such that CBAC=21.
The line CD is perpendicular to AB. Find the equation of CD in the form y=mx+c.
mAB=4−(−5)−6−6=−34
B1
mCD=43
M1
y−2=43(x+2)
M1
y=43x+27
A1
The length of BD is 125. Find the coordinates of the two possible positions of point D.
(x−4)2+(y+6)2=125
B1
Use y=43x+27 to eliminate one unknown
M1
(x−4)2+(43x+27+6)2=125
A1
25x2+100x−300=0
A1
Factorises or solves the quadratic
A1
(2,5)and(−6,−1)
A1
Point A has coordinates (3,-1).
A circle has equation (x−4)2+(y+3)2=5.
Given that AB is a diameter of the circle, find the coordinates of B.
(−34)+(−21) oe, soi
or using centre and point A e.g.
23+x=4 and 2−1+y=−3
or solve simultaneously the line y=-2 x+5 with the circle leading to 3 term quadratic x2−8x+15[=0] with an attempt to solve
M1
Award M1 for the 2 equations
Award the M1 for the quadratic
(5,-5)
A1