Show that the curve y=x−ln(x2+2x) has exactly one stationary point. Find the x-coordinate of this point.
dxdy=1−x2+2x2x+2 B1 for dxd(−ln(x2+2x))=x2+2x1×f(x) soi. Equates their first derivative to 0 and simplifies as far as 2(x+1)=x(x+2) oe M1 FT their dxdy. x2−2=0 or x2=2x=2 [x=−2] Justification that the negative solution should be rejected, e.g. x=−2 gives y=2−ln(2−22), which is impossible.