3.2 Functional groups: Organic compounds
- Syllabus
- First assessment 2025
- Topic
- 3.2
- Level
- SL
| Representation | What it preserves or shows |
|---|---|
| Empirical | Simplest whole-number atom ratio |
| Molecular | Actual atom counts |
| Structural/condensed | Connectivity in compact form |
| Skeletal | Carbon framework and implied hydrogen |
| Stereochemical/3D | Spatial arrangement |
Translate representations without changing atom connectivity. For a skeletal formula, count every vertex and line end as carbon, add enough hydrogens to give carbon four bonds, and write heteroatoms explicitly. Then verify both the molecular formula and the connectivity.
An empirical formula is a ratio, not necessarily the complete molecule: hydrogen peroxide has molecular formula H₂O₂ but empirical formula HO. Reduce all subscripts by their greatest common factor; if no common factor exists, the molecular and empirical formula are identical.
Matching atom totals alone cannot prove two drawings are the same compound: connectivity and, where relevant, stereochemistry must also agree. Do not reduce a molecular formula when the subscripts already have no common factor.
Representative question
State the type of structural formula shown.
skeletal
Marking guidance:
Accept stereochemical.
Do not accept structural (It is given in the QP).
| Family | Complete recognition pattern | Bounded characteristic cue |
|---|---|---|
| Halogenoalkane | C–F/Cl/Br/I | polar C–X bond |
| Alcohol / hydroxyl | C–OH, not the –OH inside –COOH | can donate and accept hydrogen bonds |
| Aldehyde | terminal –CHO carbonyl | polar C=O; terminal carbonyl |
| Ketone | –CO– between carbons | polar C=O; internal carbonyl |
| Carboxylic acid | –COOH | acidic proton and hydrogen bonding |
| Ether / alkoxy | C–O–C | oxygen accepts hydrogen bonds but has no O–H donor |
| Amine / amino | C–N without adjacent carbonyl | basic lone-pair chemistry; N–H species may donate H bonds |
| Amide / amido | –CONH₂/–CONHR/–CONR₂ | nitrogen directly attached to carbonyl |
| Ester | –COO– between carbon groups | carbonyl and single-bond O in one group |
| Phenyl | C₆H₅– attached as a substituent | aromatic ring pattern |
Identify the whole local bonding pattern before naming the group; these cues support classification, not a complete reaction mechanism.
Identify the characteristic atoms and bonding pattern first, then give the functional-group name and relevant property context.
Identify the complete bonding pattern: an aldehyde has a terminal –CHO carbonyl, a ketone has C=O between carbons, and an ester contains –C(=O)–O–. Do not label every O–H as an alcohol or every C–N as an amine without checking the neighbouring carbonyl.
Saturation describes carbon-carbon bonding: a saturated compound has only C-C single bonds, while an unsaturated compound contains at least one C=C or C≡C bond. A carbonyl C=O does not by itself make the carbon skeleton unsaturated. Identify saturation separately from identifying hydroxyl, carbonyl, carboxyl or other functional groups.
Representative question
State the structural formula, functional group name and homologous series of the CHO functional group.
| Structural formula drawing | Functional group name | Homologous series name |
|---|---|---|
isomers
Accept "same molecular formula".
3.
(e)
(ii)
Full structural
formula
Functional group
name
Homologous series
−cO′H
carbonyl
aldehyde
\end{tabular}
structure
carbonyl AND aldehyde
\end{tabular}
Accept R/C attached to functional group in the full structural formula.
Central C must have 4 bonds for M1.
Members of a homologous series share a functional-group pattern and general formula. Successive members differ by CH₂.
Recognize the series by its functional group and general formula, including alkanes, alkenes, alkynes, alcohols, aldehydes, ketones, acids, ethers, amines, amides, esters, and halogenoalkanes.
| Homologous series | Recognition pattern / common acyclic general formula |
|---|---|
| Alkane | only C-C single bonds; CXnHX2n+2 |
| Alkene / alkyne | C=C: CXnHX2n; C≡C: CXnHX2n−2 |
| Halogenoalkane | C-X; CXnHX2n+1X |
| Alcohol / ether | C-OH: CXnHX2n+1OH; C-O-C: CXnHX2n+2O |
| Aldehyde / ketone | terminal -CHO or internal C=O; CXnHX2nO |
| Carboxylic acid / ester | -COOH or -COO-; CXnHX2nOX2 |
| Primary amine / amide | -NH2: CXnHX2n+3N; -CONH2: CXnHX2n+1NO |
Moving from one member to the next adds CH₂, so molar mass and dispersion forces change gradually while the shared functional group gives similar reaction patterns. Use both the functional group and general formula: formula alone can overlap with another structural family.
Representative question
State the general formula for the homologous series of alkenes.
CnH2n
Subscripts of numbers not
essential
Melting and boiling points depend on chain length, branching, polarity, and intermolecular-force strength. Larger molecules often have stronger dispersion forces, while branching changes contact and packing.
Explain a comparison by naming the relevant structural difference and the resulting change in intermolecular attraction or packing.
Straight-chain pentane has a larger contact surface and higher boiling point than more highly branched isomers of the same formula; lengthening a series usually strengthens dispersion forces. For different functional groups, include polarity and hydrogen bonding before attributing the trend to size alone.
Representative question
Explain why the boiling point increases from methane to propane.
London/dispersion forces «only»
strength «of intermolecular forces» increases as size of electron cloud/number of electrons increases
Marking guidance:
Accept strength of intermolecular forces
increases as mass/size of molecule
increases for M2.
| Step | Naming decision |
|---|---|
| 1 | Choose the longest parent chain |
| 2 | Number to give the relevant feature the lowest locant |
| 3 | Identify unsaturation and functional group |
| 4 | Assemble prefixes, locants, and suffix |
Apply the systematic sequence to saturated or mono-unsaturated compounds with up to six carbons and one functional-group type.
For CH₃CH(OH)CH(CH₃)CH₃, choose the four-carbon chain containing –OH, number from the end that gives –OH the lower locant, and name 3-methylbutan-2-ol. The principal suffix controls numbering before a substituent does; check locants, punctuation and retained unsaturation at the end.
Representative question
Deduce the systematic name of X using IUPAC nomenclature.
3,5,5-trimethylhexanal
Marking guidance:
Accept 5,5,3 instead of 3,5,5 do not penalize missing hyphen/dash
Structural isomers have the same molecular formula but different atom connectivities. Types include straight-chain/branched, position, and functional-group isomers.
Classify primary, secondary, and tertiary alcohols, halogenoalkanes, and amines by the carbon or nitrogen environment attached to the functional group.
| Family | Primary / secondary / tertiary test |
|---|---|
| Alcohol | count carbon groups attached to the carbon bearing -OH: 1 / 2 / 3 |
| Halogenoalkane | count carbon groups attached to the carbon bearing X: 1 / 2 / 3 |
| Amine | count carbon groups attached directly to N: 1 / 2 / 3 |
C₄H₁₀O can represent different carbon skeletons, different –OH positions, or an ether instead of an alcohol. Draw each connectivity once, then compare molecular formulae. Rotating or redrawing one connectivity does not create a new structural isomer.
For alcohols and halogenoalkanes, classify the carbon carrying the functional group; for amines, classify the nitrogen by how many carbon groups are bonded to it. Do not use the position number alone: butan-2-ol is secondary because its OH-bearing carbon is attached to two other carbons.
Representative question
Draw a structural isomer of molecule X.
any structural isomer of CH3CHBrC(CH3)3.
Retrieve the route: translate formulae, identify functional groups and series, name and classify isomers, then use mass, IR, and NMR evidence together to determine structure.
Check connectivity, functional-group evidence, formula/mass constraint, shifts and integration, splitting neighbours, and agreement across every technique.