1.3 Electron configurations
- Syllabus
- First assessment 2025
- Topic
- 1.3
- Level
- SL
An emission photon is released when an electron falls from a higher energy state to a lower energy state. Absorption moves an electron upward and requires photon energy.
| Spectrum | What it contains | Why |
|---|---|---|
| Line spectrum | Specific wavelengths, frequencies, energies, or colours | Electrons occupy discrete energy levels, so only particular transitions occur |
| Continuous spectrum | A continuous range across the relevant values | The radiation spans the range rather than appearing as separated lines |
Across electromagnetic radiation, shorter wavelength means higher frequency, and higher frequency means higher photon energy. Explain the electron direction and photon exchange when distinguishing absorption from emission.
Read every spectral transition in two directions: absorption raises an electron by ΔE, while a downward transition emits a photon with ΔE = hf = hc/λ. A shorter-wavelength line therefore represents a larger energy gap, not a higher line intensity.
Orient the spectrum before comparing lines: radio → microwave → infrared → visible → ultraviolet → X-ray → gamma is increasing frequency and photon energy, and decreasing wavelength. Within visible light, red has longer wavelength and lower photon energy than violet.
Structured questions ask learners to distinguish absorption from emission by the direction of electron movement and photon transfer, and to distinguish continuous spectra from line spectra by their wavelength or frequency coverage.
distinguish
State the direction of the electron transition and whether a photon is absorbed or emitted, then classify a continuous spectrum as spanning the range and a line spectrum as containing only specific wavelengths, frequencies, energies, or colours.
Reversing absorption and emission, or describing a line spectrum as continuous rather than as discrete allowed wavelengths or frequencies.
Representative question
Distinguish between the processes within the atom that give rise to absorption and emission spectra.
Absorption spectra:
Emission spectra:
Absorption spectra: electrons absorb a photon/light/wavelength/frequency/energy/radiation and move to higher energy level(s);
Marking guidance:
Accept "excited state(s)" for "higher energy level(s)".
Emission spectra:
(excited) electrons move down to lower energy level(s) and release a photon/light/wavelength/frequency/energy/radiation;
Accept "state" for "level" throughout.
Award [1 max] if the movement between energy levels is described correctly but the involvement of a photon/light/wavelength/frequency/energy/radiation is omitted. Accept suitable diagrams.
Hydrogen's emission spectrum contains discrete lines because electrons occupy discrete energy levels. Each line corresponds to a downward transition and the emitted photon's energy equals the energy difference between the levels.
| Transition ending at | Region identified in the study guide |
|---|---|
| n = 1 | ultraviolet |
| n = 2 | visible |
| n = 3 | infrared |
At higher energy, the levels become closer together, so the lines converge. The names of the series are not required.
Use the presence of separate lines as evidence for discrete levels, and use convergence at higher energy or frequency as evidence that the level spacing becomes smaller.
Compare lines by their energy gaps. Transitions ending at n = 2 form the visible series, and lines crowd together as the starting level rises because adjacent high-n levels are closer in energy. The convergence limit represents removal of the electron, not one more bound-state transition.
Structured questions ask learners to describe hydrogen's discrete line spectrum and explain how each line corresponds to an electron energy difference and how the lines converge at higher energy.
describe / explain
Identify discrete lines or specific wavelengths/frequencies, connect each line to a downward transition and its energy difference, and state that energy levels become closer together at higher energy, producing convergence.
Calling the hydrogen spectrum continuous, reversing the downward emission transition, or placing convergence at lower rather than higher energy or frequency.
Representative question
Explain how this spectrum is related to the electron energy levels in a hydrogen atom.
each transition/line is related to energy difference /ΔE=λhf/hv/hc;
energy levels in hydrogen atom are closer/converge at higher energy;
A main energy level, or shell, is identified by the principal quantum number n = 1, 2, 3, and so on.
maximumelectrons=2n2
| n | Maximum electrons |
|---|---|
| 1 | 2 |
| 2 | 8 |
| 3 | 18 |
| 4 | 32 |
Substitute the stated n value into 2n²; do not confuse the shell number with the capacity.
For n = 3, the theoretical capacity is 2(3²) = 18 electrons. This is a capacity, not a claim that every third shell is full: the actual occupancy depends on the atom and the relative energies of available sublevels.
Short multiple-choice questions ask learners to calculate the maximum electron capacity for a stated main energy level using the 2n² rule.
state
Substitute the stated integer n into 2n² and select or state the resulting maximum electron count.
Using n² instead of 2n², or confusing a main energy level's total capacity with the capacity of one subshell or orbital.
Representative question
What is the maximum number of electrons that can occupy the n=3 main energy level?
3
8
18
28
C
A main energy level contains only the sublevels allowed by its principal quantum number: n = 1 has s; n = 2 has s and p; n = 3 has s, p and d; and n = 4 can include s, p, d and f. Within one main level the sublevels rise in energy s < p < d < f, while the filling order across different levels can interleave, as the next card makes explicit. Each sublevel contains a fixed number of orbitals.
| Sublevel | Number of orbitals | Maximum electrons | Assessed shape evidence | Periodic-table block |
|---|---|---|---|---|
| s | 1 | 2 | spherical | s block |
| p | 3 | 6 | three dumbbell orbitals with different orientations | p block |
| d | 5 | 10 | shape detail not required here | d block |
| f | 7 | 14 | shape detail not required here | f block |
The block is identified by the subshell being filled; sublevel capacity is not the same as actual occupancy.
For recognition questions, keep the hierarchy clear: main energy level → sublevel → orbital. The s and p shapes are the explicitly required shape evidence here.
Use the hierarchy as a classification test: a p sublevel contains three orbitals, and each orbital can hold two electrons. An orbital describes a probability region with a characteristic shape; it is not a circular route travelled by an electron.
Questions ask students to recognize or sketch the characteristic s-orbital sphere and p-orbital dumbbell, with labels where required.
sketch
Match each orbital label to its shape and show the p-orbital lobes with the correct orientation; keep the orbital-shape model distinct from the number of orbitals in a sublevel and from the periodic-table block label.
Drawing an s orbital as a dumbbell or a p orbital as a sphere
Representative question
Sketch the shapes of two different orbital types in the second energy level and label each orbital.
s-orbital
p-orbital
correct shape AND label for each. .
The p orbital must be aligned with an axis and the node must be at or close to the origin.
Accept p-orbital aligned to any of the three axes.
Aufbau fills lower-energy orbitals first. Pauli limits an orbital to two electrons with opposite spins. Hund's rule places electrons singly in degenerate orbitals before pairing.
| Representation | Use |
|---|---|
| Full configuration | Show the complete filling sequence |
| Condensed configuration | Replace the inner electrons with a noble-gas core |
| Orbital-box diagram | Show orbital occupancy and opposite-spin pairing |
For ions, remove 4s electrons before 3d electrons. The exceptions in scope are Cr: [Ar] 4s1 3d5 and Cu: [Ar] 4s1 3d10.
Check total electrons, obey the filling order, apply Hund and Pauli in each sublevel, and treat the Cr/Cu exceptions explicitly rather than forcing the naive pattern.
Build an orbital diagram by checking electron total, energy order, single occupation of equal-energy orbitals, then opposite-spin pairing. For transition-metal ions remove 4s electrons before 3d, and verify Cr and Cu against the stated exceptions rather than forcing the simple filling pattern.
Worked ion check: Fe has 26 electrons and condensed configuration [Ar] 4s² 3d⁶. To form Fe³⁺, remove the two electrons from the highest principal level, 4s, before removing one 3d electron, giving [Ar] 3d⁵. The final superscripts total 23 electrons, matching 26 − 3.
Questions ask students to draw and label a ground-state orbital diagram or select/configure an atom using the filling rules and the Cr/Cu exceptions.
draw
Fill orbitals in the stated energy order, place one electron in each degenerate orbital before pairing, pair only opposite spins, remove 4s electrons before 3d for transition-metal ions, and use the accepted Cr/Cu exception configurations.
Pairing electrons in a p or d sublevel before singly occupying equivalent orbitals
Representative question
Draw the orbital diagram of the phosphorus atom in the ground state by adding, filling and labelling the orbitals. Use section 7 of the data booklet.
2s
1s
3p
□
1
3rd shell orbitals must be higher than
2nd shell for M2.
3s
□
2 p
2s □ 1
correct labels
correct electron configuration
Retrieve the chain: emission lines reveal discrete levels; capacities, sublevels, orbitals, and spin rules build configurations; first and successive ionization energies then reveal how electrons are held and arranged.
When checking an answer, ask: Did I link a line to a transition? Did I use 2n² and the filling rules? Did I explain an ionization trend or count electrons before a successive-IE jump?