IB Chemistry HL 1.5.3 Molar Volume Question Bank
Practise IB Chemistry HL 1.5.3 with questions converting gas volume and amount using molar-volume conditions and units.
- Syllabus
- First assessment 2025
- Course
- Chemistry HL
- Level
- HL
Practise IB Chemistry HL 1.5.3 with questions converting gas volume and amount using molar-volume conditions and units.
Two hydrides of nitrogen are ammonia and hydrazine, N2H4. One derivative of ammonia is methanamine whose molecular structure is shown below.

Calculate, showing your working, the mass of hydrazine needed to remove all the dissolved oxygen from 1000dm3 of the sample.
Calculate the volume, in dm3, of nitrogen formed under SATP conditions.
(The volume of 1 mol of gas =24.8dm3 at SATP.)
n(N2H4)=n(O2)=32.00 g mol−18.0 g=0.25 molvolume of nitrogen=0.25 mol×24.8 dm3 mol−1=6.2 dm3
Award [1] for the correct final answer.