AP Biology 5.2 Meiosis and Genetic Diversity
Practise AP Biology 5.2 questions by connecting meiotic chromosome behavior, recombination and nondisjunction with variation among gametes.
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- Effective Fall 2025
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- AP Biology
Practise AP Biology 5.2 questions by connecting meiotic chromosome behavior, recombination and nondisjunction with variation among gametes.
Crossing over in meiosis I is required for homologous chromosomes to properly align during metaphase and segregate during the first cell division.
Explain why some haploid cells formed after meiosis in this experiment will have only one fluorescent marker.
The scientists then investigated whether attaching individual kinetochore proteins to a specific DNA sequence present in a known crossing-over hotspot on chromosome 8 affected the frequency of crossing over at this location. In their first experiment, they examined three groups of yeast cells containing the modified chromosome 8. Group 1 contained no kinetochore proteins attached to the hotspot, group 2 contained the kinetochore protein CTF attached to the hotspot, and group 3 contained the kinetochore protein IML attached to the hotspot. For each group, the scientists determined the frequency of crossing over between the RFP and GFP genes. To determine the frequency, the scientists added the number of cells emitting both red and green light to the number of cells that emitted no light and divided by the total number of cells (Figure 2).

Figure 2. The frequency of crossing over in a hotspot on yeast chromosome 8 for cell groups treated with different kinetochore proteins. Error bars represent \(\pm 2 \mathrm{SE
Explain why some haploid cells formed after meiosis in this experiment will have only one fluorescent marker.
Accept one of the following:
- Some cells will receive a chromosome/(sister) chromatid that did not undergo
crossing over/recombination (in the hotspot).
- Each daughter cell will receive one of the four sister chromatids. Two of the sister
chromatids shown in Figure 1 have only one fluorescent protein gene.
- The two chromosomes that were not involved in crossing over will have only the RFP gene or the GFP gene. After meiosis II, a gamete with one of these
chromosomes will have only the RFP or the GFP gene.
1 point
Total for part (a)
2 points
Based on Figure 2, describe the effect on the frequency of crossing over when CTF is attached to the chromosome 8 hotspot compared with the effect when IML is attached to the hotspot.
Based on Figure 2, describe the effect on the frequency of crossing over when CTF is attached to the chromosome 8 hotspot compared with the effect when IML is attached to the hotspot.
Accept one of the following:
- CTF attachment results in a decreased/lower frequency of crossing over/recombination, (whereas IML had no effect).
- IML attachment results in an increased/a higher frequency of crossing over/recombination (compared with CTF attachment).
1 point
Predict the effect on the number of copies of chromosome 8 likely to be present in the resulting daughter cells when CTF is attached to the hotspot.
Accept one of the following:
- There will be zero/two (copies).
- There will be one less/one extra (copy).
1 point
Provide reasoning to justify your prediction.
Provide reasoning to justify your prediction.
- Cells (with attached CTF molecules) undergo crossing over/recombination at a
lower frequency, so it is more likely that nondisjunction would occur/chromosomes would not separate properly.
1 point
Explain how the presence of hotspots (Figure 1) could increase the likelihood that a population will survive in the presence of selective pressures.
Write your responses to this question only on the designated pages in the separate Free Response booklet. If there are multiple parts to this question, write the part letter with your response.
Explain how the presence of hotspots (Figure 1) could increase the likelihood that a population will survive in the presence of selective pressures.
- Hotspots would increase genetic diversity; therefore, it would be more likely that some individuals would survive and reproduce. 1 point
Total for part (d) for question 19 points