Pearson Edexcel IAL Mathematics P1.5 Integration Question BankPractise reversing differentiation to integrate powers, roots and expanded expressions, including using points to recover f(x).SyllabusFirst assessment 2019CourseMathematics YMA01LevelAS
Exam pointsintegrate powers, roots and reciprocal powers of x, keeping answers in simplest formrecover f(x) from f'(x), then use a point on the curve to find the constantexpand products before integrating when the integrand is not already a sum of powers
P1.5 - Integration question 1[Maximum number: 7]The curve C has equation y=f(x) where x>0Given that- f′(x)=(x+3)2xx\mathrm{f}^{\prime}(x)=\frac{(x+3)^{2}}{x \sqrt{x}}f′(x)=xx(x+3)2- the point P(4,20) lies on CFind f(x), simplifying your answer.Show Answerf′(x)=(x+3)2xx=x2+6x+9xxf'(x)=\frac{(x+3)^2}{x\sqrt{x}}=\frac{x^2+6x+9}{x\sqrt{x}}f′(x)=xx(x+3)2=xxx2+6x+9=x1/2+6x−1/2+9x−3/2=x^{1/2}+6x^{-1/2}+9x^{-3/2}=x1/2+6x−1/2+9x−3/2f(x)=23x3/2+12x1/2−18x−1/2+cf(x)=\frac23x^{3/2}+12x^{1/2}-18x^{-1/2}+cf(x)=32x3/2+12x1/2−18x−1/2+c20=23(4)3/2+12(4)1/2−18(4)−1/2+c⇒c=−1320=\frac23(4)^{3/2}+12(4)^{1/2}-18(4)^{-1/2}+c\Rightarrow c=-\frac1320=32(4)3/2+12(4)1/2−18(4)−1/2+c⇒c=−31f(x)=23x3/2+12x1/2−18x−1/2−13f(x)=\frac23x^{3/2}+12x^{1/2}-18x^{-1/2}-\frac13f(x)=32x3/2+12x1/2−18x−1/2−31M1 A1 dM1 A1 A1 M1 A1Add to Test