Pearson Edexcel IAL Mathematics P1.5.2 Integration of powers of x & related sumsPractise integrating sums of powers of x, including roots, reciprocal powers and expanded products, with answers simplified.SyllabusFirst assessment 2019CourseMathematics YMA01LevelAS
Exam pointsrewrite roots and reciprocals as powers before integrating term by termuse a point on the curve to determine c after finding f(x) from f'(x)
P1.5.2 - Integration of powers of x and related sums question 1[Maximum number: 7]The curve C has equation y=f(x) where x>0Given that- f′(x)=(x+3)2xx\mathrm{f}^{\prime}(x)=\frac{(x+3)^{2}}{x \sqrt{x}}f′(x)=xx(x+3)2- the point P(4,20) lies on CFind f(x), simplifying your answer.Show AnswerMark as masteredf′(x)=(x+3)2xx=x2+6x+9xxf'(x)=\frac{(x+3)^2}{x\sqrt{x}}=\frac{x^2+6x+9}{x\sqrt{x}}f′(x)=xx(x+3)2=xxx2+6x+9=x1/2+6x−1/2+9x−3/2=x^{1/2}+6x^{-1/2}+9x^{-3/2}=x1/2+6x−1/2+9x−3/2f(x)=23x3/2+12x1/2−18x−1/2+cf(x)=\frac23x^{3/2}+12x^{1/2}-18x^{-1/2}+cf(x)=32x3/2+12x1/2−18x−1/2+c20=23(4)3/2+12(4)1/2−18(4)−1/2+c⇒c=−1320=\frac23(4)^{3/2}+12(4)^{1/2}-18(4)^{-1/2}+c\Rightarrow c=-\frac1320=32(4)3/2+12(4)1/2−18(4)−1/2+c⇒c=−31f(x)=23x3/2+12x1/2−18x−1/2−13f(x)=\frac23x^{3/2}+12x^{1/2}-18x^{-1/2}-\frac13f(x)=32x3/2+12x1/2−18x−1/2−31M1 A1 dM1 A1 A1 M1 A1Add to Test