Edexcel IAL Mathematics P1.1.2 use and manipulate surdsSurd questions reward exact working: simplify roots, rationalise conjugate denominators and keep answers in exact requested forms.SyllabusFirst assessment 2019CourseMathematics YMA01LevelAS
Exam pointsSimplify exact lengths such as QR = 2√2x from Pythagoras-style expressions.Rationalise denominators with conjugates to give a√2 + b or p√3 + q forms.Solve equations involving √3 terms and present x in the requested exact surd form.
P1.1.2 - Use and manipulate surds question 1[Maximum number: 5]In this question you must show all stages of your working.Solutions relying on calculator technology are not acceptable.Question (a)(a)Show that 180−805\frac{\sqrt{180}-\sqrt{80}}{\sqrt{5}}5180−80 is an integer and find its value.[ 2 ]Show AnswerWrites 180\sqrt{180}180 as 656 \sqrt{5}65 or 80\sqrt{80}80 as 454 \sqrt{5}45M1Concludes working 65−455=255=2\frac{6 \sqrt{5}-4 \sqrt{5}}{\sqrt{5}}=\frac{2 \sqrt{5}}{\sqrt{5}}=2565−45=525=2A1(2)Question (b)(b)Simplify45−57−35\frac{4 \sqrt{5}-5}{7-3 \sqrt{5}}7−3545−5giving your answer in the form a+b5a+b \sqrt{5}a+b5 where a and b are rational numbers.[ 3 ]Show Answer45−57−35=45−57−35×7+357+35\frac{4\sqrt5-5}{7-3\sqrt5} =\frac{4\sqrt5-5}{7-3\sqrt5}\times\frac{7+3\sqrt5}{7+3\sqrt5}7−3545−5=7−3545−5×7+357+35=285−35+12(5)2−15549−9×5=\frac{28\sqrt5-35+12(\sqrt5)^2-15\sqrt5}{49-9\times5}=49−9×5285−35+12(5)2−155=254+1345=\frac{25}{4}+\frac{13}{4}\sqrt5=425+4135M1 dM1 A1Marking guidance for this part:M1 for a correct attempt to rationalise by multiplying by 7+357+3\sqrt57+35.dM1 for a surd-free denominator and an attempt to multiply out the numerator with four terms.A1 for 254+1345\frac{25}{4}+\frac{13}{4}\sqrt5425+4135.Add to Test
Question (a)(a)Show that 180−805\frac{\sqrt{180}-\sqrt{80}}{\sqrt{5}}5180−80 is an integer and find its value.[ 2 ]Show AnswerWrites 180\sqrt{180}180 as 656 \sqrt{5}65 or 80\sqrt{80}80 as 454 \sqrt{5}45M1Concludes working 65−455=255=2\frac{6 \sqrt{5}-4 \sqrt{5}}{\sqrt{5}}=\frac{2 \sqrt{5}}{\sqrt{5}}=2565−45=525=2A1(2)
Question (b)(b)Simplify45−57−35\frac{4 \sqrt{5}-5}{7-3 \sqrt{5}}7−3545−5giving your answer in the form a+b5a+b \sqrt{5}a+b5 where a and b are rational numbers.[ 3 ]Show Answer45−57−35=45−57−35×7+357+35\frac{4\sqrt5-5}{7-3\sqrt5} =\frac{4\sqrt5-5}{7-3\sqrt5}\times\frac{7+3\sqrt5}{7+3\sqrt5}7−3545−5=7−3545−5×7+357+35=285−35+12(5)2−15549−9×5=\frac{28\sqrt5-35+12(\sqrt5)^2-15\sqrt5}{49-9\times5}=49−9×5285−35+12(5)2−155=254+1345=\frac{25}{4}+\frac{13}{4}\sqrt5=425+4135M1 dM1 A1Marking guidance for this part:M1 for a correct attempt to rationalise by multiplying by 7+357+3\sqrt57+35.dM1 for a surd-free denominator and an attempt to multiply out the numerator with four terms.A1 for 254+1345\frac{25}{4}+\frac{13}{4}\sqrt5425+4135.