dentroom.
B1ft.Wordyrees
B1
B1ft
B1
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Total weight of the MST is therefore 14 x+5 y-4
A1
14 x+5 y-4=73 and testing integer value points inside FR
M1dep
x=3 and y=7
A1
15 marks
Notes for Question 7
a1M1: Explaining that if CD is not in the tree than AD must be e.g. 'the MST must contain D so if CD is not in the tree then AD is'. Must explicitly mention arc AD for this mark, so as a minimum accept, 'AD must be in the MST'
a1A1: Correct reasoning and derivation of the given result ( 2y+x>3y−7⇒y<x+7 ) - as the answer is given we must see at least 2 y+x>3 y-7 or 3 y-7<2 y+x before the required answer
SC (Special Case) in (a): 2y+x>3y−7⇒y<x+7 without any explanation given (or if explanation is incorrect) can score M1A0
b1B1: CAO - must see at least 4 x+1<2 y+1 before the given answer of y>2 x and not just arc AB<arc AC or 4 x<2 y
b2B1: CAO (x>1) - but allow equivalents, e.g., x-1>0,1<x, 4 x>4, etc. but must be two terms only b3B1: CAO (3 y>4 x+8) - but allow exact equivalents e.g. y>34x+38,4x−3y<−8,4x+8−3y<0, or equivalent but must be three terms only
In (c), the lines can be drawn as either dashed or non-dashed lines (or a combination of the two). The lines must be long enough to define the correct feasible region and pass through one small square of the points stated below:
y=2 x must pass within one small square of (0,0) and (7,14)
y=x+7 must pass within one small square of (0,7) and (7,14)
x=1 must pass within one small square of (1,0) and (1,10)
3 y=4 x+8 must pass within one small square of (1,4) and (7,12)
c1B1: Any one line correctly drawn (ignore any shading)
c2B1: Any two lines correctly drawn (ignore any shading)
c3B1: Any three lines correctly drawn (ignore any shading)
c4B1: All four lines correctly drawn and shading which implies the correct region (but region need not be labelled)