ConceptConceptDocsDocuments

Edexcel IAL Chemistry 6.P4 evaluate results and conclusions

The two direct questions both test the same judgement: explain whether a lycopene value read from a graph is valid by referring to the range of plotted data.

Syllabus
First assessment 2019
Course
Chemistry YCH11
Level
A2

Exam points

  • Judge whether a graph-derived lycopene concentration is valid from the plotted data range.

6.P4—Evaluating results and conclusions question 1

[Maximum number: 1]

This question is about the nitration of methyl benzoate.

The equation for the reaction is shown.

Figure for Question 6.P4—Evaluating results and conclusions question 1 — Edexcel A-Level Chemistry A2

Procedure

Step 1 Weigh between 1.9 g and 2.1 g of methyl benzoate in a 50 cm350 \mathrm{~cm}^{3} conical flask.
Step 2 Slowly add 5 cm35 \mathrm{~cm}^{3} of concentrated sulfuric acid to the methyl benzoate with swirling and place the flask in an ice-water bath to cool.

Step 3 Place 2.0 cm32.0 \mathrm{~cm}^{3} of concentrated nitric acid into a test tube.
Cool the nitric acid by immersing the test tube in an ice-water bath before slowly adding 2.0 cm32.0 \mathrm{~cm}^{3} of concentrated sulfuric acid.
Allow this nitrating mixture to cool.
Step 4 Using a teat pipette, add the nitrating mixture very slowly to the conical flask, ensuring the temperature does not exceed 7C7^{\circ} \mathrm{C}.

Step 5 Allow the flask to stand at room temperature for about 15 minutes and then pour the contents into a beaker containing some crushed ice. Impure methyl 3-nitrobenzoate will form.

Step 6 Recrystallise the methyl 3-nitrobenzoate using methanol as the solvent.
Step 7 Weigh the dry crystals and determine their melting temperature.

1.95 g of methyl benzoate reacted with an excess of nitric acid to form
1.51 g of methyl 3-nitrobenzoate.
[Molar mass values: methyl benzoate, C6H5CO2CH3=136 g mol1\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CO}_{2} \mathrm{CH}_{3}=136 \mathrm{~g} \mathrm{~mol}^{-1}
methyl 3-nitrobenzoate, C6H4CO2CH3NO2=181 g mol1\mathrm{C}_{6} \mathrm{H}_{4} \mathrm{CO}_{2} \mathrm{CH}_{3} \mathrm{NO}_{2}=181 \mathrm{~g} \mathrm{~mol}^{-1} ]

Give one possible reason why the yield in (d)(i) is less than 100\%.

All question bank results loaded