Edexcel A-Level Chemistry A2 17.28 Understand in Terms of Oxidation Number How V2o5 Acts As a Catalyst in the Contact Process Questions

Write the two-step catalyst cycle: sulfur dioxide reduces V2O5 to V2O4, then oxygen reoxidises V2O4 back to V2O5 while sulfur trioxide forms.

Syllabus
First assessment 2019
Course
Chemistry YCH11
Level
A2

Exam points

  • Write catalyst-cycle equations for V2O5 reduced by SO2 and V2O4 reoxidised by O2.
  • State the vanadium oxidation number cycle as +5 to +4 and back to +5 in V2O5.
  • Identify sulfuric acid manufacture as the process using a V2O5 catalyst.

Edexcel A-Level Chemistry A2 17.28 Understand in Terms of Oxidation Number How V2o5 Acts As a Catalyst in the Contact Process Questions question 1

[Maximum number: 2]

This question is about the chemistry of vanadium.
The standard electrode potentials of some vanadium species are shown.

Table for Question Edexcel A-Level Chemistry A2 17.28 Understand in Terms of Oxidation Number How V2o5 Acts As a Catalyst in the Contact Process Questions question 1 — Edexcel A-Level Chemistry A2

In the manufacture of sulfuric acid, vanadium(V) oxide, V_2 O_5, is the catalyst used in the conversion of sulfur dioxide to sulfur trioxide:

2SO2+O22SO32 \mathrm{SO}_{2}+\mathrm{O}_{2} \rightleftharpoons 2 \mathrm{SO}_{3}

Write two equations to show a possible mechanism for this reaction.
State symbols are not required.

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