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18.3—Why benzene is resistant to bromination, compared to alkenes, in terms of delocalisation of π-bonds in benzene compared

Syllabus
2017
Objective
18.3
Level
A2

—Why benzene is resistant to bromination, compared to alkenes, in terms of delocalisation of π-bonds in benzene compared

Understand why benzene is resistant to bromination, compared to alkenes, in terms of delocalisation of π-bonds in benzene compared to the localised electron density of the π-bond in alkenes.

Use —why benzene is resistant to bromination, compared to alkenes, in terms of delocalisation of π-bonds in benzene compared to connect the rule to the data and decision in the question.

This matters because —why benzene is resistant to bromination, compared to alkenes, in terms of delocalisation of π-bonds in benzene compared determines what can be inferred or chosen; begin with the stated conditions and keep the conclusion tied to the evidence.

Example: apply —why benzene is resistant to bromination, compared to alkenes, in terms of delocalisation of π-bonds in benzene compared to one small, clearly defined case, show the key step or comparison, and explain the result in words.

Boundary: —Why benzene is resistant to bromination, compared to alkenes, in terms of delocalisation of π-bonds in benzene compared is not a universal recommendation. Check the syllabus scope, assumptions, units and the limits of the evidence before generalising.

ConceptA-Level Edexcel Chemistry A2