Topic 18: Organic Chemistry A2 – Arenes

Syllabus
2017
Topic
Level
A2

Learning objectives

18.1Thermochemical, X-ray diffraction and infrared data as evidence for the structure and stability of the benzene ring StudentsBe able to use thermochemical, X-ray diffraction and infrared data as evidence for the structure and stability of the benzene ring Students may represent the structure of benzene as or as appropriate in equations and mechanisms.18.2The delocalised model for the structure of benzene involves overlap of p-orbitals to form π-bondsUnderstand that the delocalised model for the structure of benzene involves overlap of p-orbitals to form π-bonds18.3Why benzene is resistant to bromination, compared to alkenes, in terms of delocalisation of π-bonds in benzene comparedUnderstand why benzene is resistant to bromination, compared to alkenes, in terms of delocalisation of π-bonds in benzene compared to the localised electron density of the π-bond in alkenes18.4The following reactions of benzeneKnow the following reactions of benzene, limited to: i oxygen in air (combustion to form a smoky flame) ii bromine, in the presence of a catalyst iii a mixture of concentrated nitric and sulfuric acids iv fuming sulfuric acid v halogenoalkanes and acyl chlorides with aluminium chloride as catalyst (Friedel-Crafts reaction)18.5The mechanism of the electrophilic substitution reactions of benzene in halogenation, nitration and Friedel-Crafts reactionsUnderstand the mechanism of the electrophilic substitution reactions of benzene in halogenation, nitration and Friedel-Crafts reactions, including the generation of the electrophile18.6The reaction of phenol with bromine water and the reasons for the relative ease of this reaction compared to benzeneUnderstand the reaction of phenol with bromine water and the reasons for the relative ease of this reaction compared to benzene

Three kinds of evidence support a delocalised benzene ring

Evidence Observation Structural conclusion
thermochemical three isolated C=C bonds would hydrogenate by about 3 × -120 = -360 kJ mol^-1, but benzene is about -208 kJ mol^-1 benzene is about 152 kJ mol^-1 more stable than the localised cyclohexa-1,3,5-triene model
X-ray diffraction all six C-C bonds have the same length, intermediate between typical C-C and C=C the ring does not contain three fixed single and three fixed double bonds
infrared all ring C-C bonds give the same aromatic stretching pattern, rather than separate fixed C-C/C=C sets the six carbon-carbon bonds are equivalent

The evidence is consistent with six π electrons delocalised around a planar six-carbon ring. Benzene may be drawn as a hexagon with a circle or as a Kekulé hexagon when equations and curly-arrow mechanisms require explicit electron movement.

A Kekulé drawing is a representation, not evidence that benzene rapidly switches between two localised structures. The measured molecule has equivalent bonds and additional delocalisation stability.

Continuous p-orbital overlap forms benzene's delocalised π system

Each carbon in benzene is trigonal planar and uses three orbitals to make σ bonds: two C-C bonds in the ring and one C-H bond. This leaves one unhybridised p orbital perpendicular to the ring plane on every carbon.

The six parallel p orbitals overlap sideways with both neighbours. Their electron density joins into one continuous delocalised π system above and below the carbon ring, containing six π electrons rather than three isolated electron pairs.

Because the π electrons are shared across all six carbon atoms, every C-C bond has the same order, length and strength, intermediate between a localised single and double bond.

The π system is formed from overlapping p orbitals; there are not six separate 'π orbitals' or three fixed π bonds located on alternating edges.

Delocalisation makes benzene harder to brominate than an alkene

Feature Alkene Benzene
π electron density localised between two carbons spread around six carbons
attraction/polarisation of Br2 strong enough under normal conditions weaker; an electrophile must be generated with a catalyst
reaction electrophilic addition, rapidly decolourises bromine electrophilic substitution, requiring FeBr3/Fe and heat
stability cost local π bond is replaced high-energy intermediate temporarily loses aromatic delocalisation

Benzene can react with an electrophile, but formation of the non-aromatic intermediate has a larger activation-energy barrier. Substitution then restores the delocalised ring; addition would destroy its stabilisation in the product.

The delocalised electrons do not repel electrophiles. Benzene is less reactive because its π density is spread out and disrupting aromatic delocalisation creates a kinetic barrier.

Know the five specified reaction families of benzene

Reaction Reagent/conditions Organic product or observation
combustion oxygen in air CO2 and H2O in complete combustion; smoky flame because of high carbon content
bromination Br2 with FeBr3 (or Fe forming catalyst), heat bromobenzene + HBr
nitration concentrated HNO3 + concentrated H2SO4, warm nitrobenzene + H2O
sulfonation fuming H2SO4 benzenesulfonic acid
Friedel-Crafts alkylation halogenoalkane + anhydrous AlCl3 alkylbenzene + HX
Friedel-Crafts acylation acyl chloride + anhydrous AlCl3 aryl ketone + HCl

\ce{C6H6 + CH3COCl ->[AlCl3] C6H5COCH3 + HCl}

The syllabus list is deliberately limited. Keep the catalysts and concentrated/fuming conditions distinct, and do not substitute a carboxylic acid for the acyl chloride in Friedel-Crafts acylation.

Electrophilic substitution restores the aromatic π system

Reaction Electrophile generation Electrophile
bromination Br2 + FeBr3 → Br+ + FeBr4- Br+
nitration HNO3 + H2SO4 → NO2+ + HSO4- + H2O NO2+
Friedel-Crafts alkylation RCl + AlCl3 → R+ + AlCl4- R+
Friedel-Crafts acylation RCOCl + AlCl3 → RCO+ + AlCl4- RCO+
  1. A curly arrow starts from the benzene π system and ends at E+, forming a C-E bond and a positively charged non-aromatic intermediate. 2. A base removes H+ from that carbon; the curly arrow from the C-H bond returns into the ring and restores delocalisation. The net result is replacement of H by E.

The catalyst is regenerated: FeBr4- + H+ → HBr + FeBr3, or AlCl4- + H+ → HCl + AlCl3. In nitration, HSO4- accepts H+ to regenerate H2SO4.

Curly arrows begin at electron pairs or bonds, never at a positive charge. The first step disrupts aromaticity; the second must restore the ring rather than produce an addition product.

Phenol brominates without a catalyst because oxygen activates the ring

\ce{C6H5OH + 3Br2 -> 2,4,6-C6H2Br3OH + 3HBr}

Starting material Bromine conditions Result
benzene Br2 requires FeBr3/Fe and heat bromobenzene by substitution
phenol bromine water at room temperature, no catalyst bromine decolourises and white 2,4,6-tribromophenol precipitate forms

One lone pair on the phenol oxygen overlaps with the ring π system and donates electron density into it. The ring is therefore more electron-rich, especially at the 2, 4 and 6 positions, so it polarises bromine and undergoes electrophilic substitution much more readily than benzene.

Phenol does not react more readily because the O-H bond is acidic or because phenol is simply 'a nucleophile'. The required explanation is lone-pair overlap with the ring and increased ring electron density.