20.2 Force on a current-carrying conductor

Syllabus
9702–2028–2029
Topic
20.2
Level
A2

Learning objectives

A current-carrying conductor in a magnetic field can experience a force

A current-carrying conductor experiences magnetic force when its current has a component perpendicular to an external magnetic field.

Reverse current or field direction to reverse force. Parallel current and field produce no force in the ideal straight-wire model.

A wire between magnet poles deflects when current flows, forming the basis of a simple motor.

The force is not caused by current alone; it requires interaction with an external magnetic field.

Use F=BIL sinθ and Fleming's left hand for force on a wire

forcemagnitudeF=BILsinθforce magnitude F=BIL sinθ

Symbol Meaning
B magnetic flux density in T
I conventional current in A
L wire length within the field in m
θ angle between conventional current and magnetic field
Fleming's left-hand digit Direction
First finger magnetic Field, N to S
seCond finger conventional Current, + to -
thuMb Motion / force on conductor

At θ=90°, F=BIL is maximum. At θ=0° or 180°, F=0. Reversing either I or B reverses force; reversing both leaves force direction unchanged.

A 0.20 m wire carrying 3.0 A at 30° to a 0.50 T field experiences F=(0.50)(3.0)(0.20)sin30°=0.150 N. Use the left hand separately to give direction.

Use conventional current, not electron flow, with Fleming's rule. θ is the angle between I and B, not between force and field; the force is perpendicular to both I and B.

Magnetic flux density is force per unit current per unit perpendicular length

For a wire perpendicular to a field, B=F/(IL), measured in tesla, so 1 T=1 N A⁻¹ m⁻¹.

The definition assumes the conductor is perpendicular; otherwise divide by IL sinθ or resolve the perpendicular component.

A 0.40 N force on a 0.20 m wire carrying 2.0 A gives B=1.0 T when perpendicular.

Tesla is not force per charge; that relates to electric field, while B describes magnetic force on current or moving charge.