3.5.5—Inverse tangent
- Syllabus
- 9709–2028–2029
- Objective
- 3.5.5
- Level
- A2
Use ∫du/(u²+a²)=(1/a)tan⁻¹(u/a)+C after rewriting the denominator as a square plus a positive constant.
Complete the square, factor the constant scale correctly, and use a substitution if the numerator contains the derivative of the shifted variable.
∫dx/[(x−2)²+9]=⅓tan⁻¹((x−2)/3)+C.
The coefficient is 1/a, not a; omitting it gives a derivative three times too large in the example.