EduNinja

A-Level CAIE Mathematics A23.3 TrigonometryQuestion Bank

Question 1

[Maximum number: 3]

Prove the identity cotxtanxcotx+tanxcos2x\frac{\cot x-\tan x}{\cot x+\tan x} \equiv \cos 2 x.

Question 2

Question 2(i)

(a)

Given that tan2θcotθ=8\tan 2 \theta \cot \theta=8, show that tan2θ=34\tan ^{2} \theta=\frac{3}{4}.

[ 3 ]

Question 2

[Maximum number: 5]

Showing all necessary working, solve the equation cotθ+cot(θ+45)=2\cot \theta+\cot \left(\theta+45^{\circ}\right)=2, for 0<θ<1800^{\circ}<\theta<180^{\circ}.

Question 2

[Maximum number: 5]

Solve the equation 5tan2θ=4cotθ5 \tan 2 \theta=4 \cot \theta for 0<θ<1800^{\circ}<\theta<180^{\circ}.

Question 2

Question 2(i)

(a)

Express 24sinθ7cosθ24 \sin \theta-7 \cos \theta in the form Rsin(θα)R \sin (\theta-\alpha), where R>0 and 0<α<900^{\circ}<\alpha<90^{\circ}. Give the value of α\alpha correct to 2 decimal places.

[ 3 ]

Question 2(ii)

(b)

Hence find the smallest positive value of θ\theta satisfying the equation

24sinθ7cosθ=1724 \sin \theta-7 \cos \theta=17

Question 2

[Maximum number: 5]

Solve the equation cos(θ60)=3sinθ\cos \left(\theta-60^{\circ}\right)=3 \sin \theta, for 0θ3600^{\circ} \leqslant \theta \leqslant 360^{\circ}.

Question 3

[Maximum number: 7]

It is given that cosa=35\cos a=\frac{3}{5}, where 0<a<900^{\circ}<a<90^{\circ}. Showing your working and without using a calculator to evaluate a,

Question 3(i)

(a)

find the exact value of sin(a30)\sin \left(a-30^{\circ}\right),

[ 3 ]

Question 3(ii)

(b)

find the exact value of tan2a\tan 2 a, and hence find the exact value of tan3a\tan 3 a.

[ 4 ]

Question 3

Question 3(a)

(a)

Show that (secx+cosx)2(\sec x+\cos x)^{2} can be expressed as sec2x+a+bcos2x\sec ^{2} x+a+b \cos 2 x, where a and b are constants to be determined.

[ 2 ]

Question 3

Question 3(i)

(a)

Express 8cosθ+15sinθ8 \cos \theta+15 \sin \theta in the form Rcos(θα)R \cos (\theta-\alpha), where R>0 and 0<α<900^{\circ}<\alpha<90^{\circ}. Give the value of α\alpha correct to 2 decimal places.

Question 3(ii)

(b)

Hence solve the equation 8cosθ+15sinθ=128 \cos \theta+15 \sin \theta=12, giving all solutions in the interval 0<θ<3600^{\circ}<\theta<360^{\circ}.

Question 3

Question 3(i)

(a)

Using the expansions of cos(3x+x)\cos (3 x+x) and cos(3xx)\cos (3 x-x), show that

12(cos4x+cos2x)cos3xcosx\frac{1}{2}(\cos 4 x+\cos 2 x) \equiv \cos 3 x \cos x
[ 3 ]
0 selected