4.9 Mensuration of 2D shapes
- Syllabus
- 2017
- Topic
- 4.9
- Level
- Higher
A metric conversion factor acts once on a length but is squared for an area. Since 1 m=100 cm, it follows that 1 m2=1002 cm2=10,000 cm2.
| Conversion | Length | Area |
|---|---|---|
| m to cm | multiply by 100 | multiply by 10,000 |
| cm to m | divide by 100 | divide by 10,000 |
| km to m | multiply by 1000 | multiply by 1,000,000 |
Write the unit relationship first, raise its numerical factor to the power shown by the unit, then multiply toward smaller units or divide toward larger units. Include the converted unit in the answer.
Changing 1 m2 to 100 cm2 converts only one dimension; an area has two dimensions, so the factor must be squared.
Perimeter is the total length of the exposed outer boundary. Trace the outline once and add every outside edge; internal joins do not contribute.
| Step | Action |
|---|---|
| 1 | mark the starting corner and trace clockwise |
| 2 | infer missing horizontal or vertical lengths from aligned totals |
| 3 | add only exposed edges in consistent units |
| 4 | check that the trace returns to the start |
For shapes made from identical rectangles or triangles, shared edges disappear from the perimeter. A cost per metre is applied only after the perimeter has been found.
Do not add every side of every component: doing so double-counts internal shared boundaries.
Use A=lw for a rectangle and A=21bh for a triangle, where h is perpendicular to the chosen base b.
| Shape structure | Area strategy |
|---|---|
| joined pieces | split, calculate, then add |
| cut-out region | calculate the whole, then subtract |
| repeated tiles | area of one tile × number of tiles |
Draw decomposition lines, label each base and perpendicular height, calculate in one unit, and preserve full precision before any coverage or cost decision. Round a required number of whole tins or tiles upward.
A sloping side is not a triangle's height unless it is perpendicular to the chosen base. Trigonometric area of a general triangle belongs to Topic 4.8, not this objective.
A parallelogram has area A=bh. A trapezium with parallel sides a and b has area A=21(a+b)h, where h is the perpendicular distance between them.
| Symbol | Geometric meaning |
|---|---|
| a,b | the two parallel side lengths |
| h | perpendicular separation, not a sloping side |
| 21(a+b) | average width of the trapezium |
Mark the parallel sides, identify or derive their perpendicular separation, substitute with consistent units, and rearrange the same formula if a missing length is required.
Do not average an arbitrary pair of sides, and do not use the sloping edge as h unless a right-angle condition makes it perpendicular.
For radius r and diameter d=2r, circumference is C=2πr=πd and area is A=πr2. A semicircle has half the circular arc and half the circular area.
| Measure | Semicircle result |
|---|---|
| curved arc | πr |
| perimeter | πr+2r |
| area | 21πr2 |
For a composite region, find each radius from the given diameters, then add or subtract the relevant circular and polygonal parts. Use exact π during working and round only at the end.
The perimeter of a semicircle includes its straight diameter; the area does not. Do not confuse πr2 with 2πr.
A sector with central angle θ degrees is the fraction θ/360 of a circle. Arc length is L=360θ(2πr) and area is A=360θ(πr2).
| Required boundary | Include |
|---|---|
| arc length only | curved arc L |
| sector perimeter | curved arc L plus two radii 2r |
| major sector | use 360∘−θ when the given angle describes the minor sector |
Identify the centre, radius and intended minor or major angle, calculate the circle fraction in degrees, then include only the requested boundary or area. Radian measure is outside this syllabus objective.
A segment is bounded by an arc and a chord, while a sector is bounded by an arc and two radii; their perimeters and areas are not interchangeable.