4.10 3D shapes and volume

Syllabus
2017
Topic
4.10
Level
Higher

Learning objectives

Recognise and name common solids

Name a solid from the structure of its surfaces and cross-sections, not from the way a perspective sketch happens to look.

Solid Defining feature
cube / cuboid six square / rectangular faces
prism identical parallel end faces and constant cross-section
pyramid one polygonal base; triangular faces meet at one vertex
cylinder two parallel circular ends and one curved surface
sphere every surface point is the same distance from the centre
cone circular base and curved surface meeting at one vertex

Identify any repeated parallel cross-section, then check the number and shape of plane faces and whether a curved surface or single apex is present.

A cylinder is a circular prism in some broad usage, but the syllabus expects the specific name 'cylinder'; a pyramid narrows to a point while a prism does not.

Identify faces, edges and vertices

A face is a flat surface of a polyhedron, an edge is where two faces meet, and a vertex is a corner where edges meet. Curved solids may also be described using curved surfaces and circular boundaries.

Solid Faces / surfaces Edges Vertices
cube or cuboid 6 12 8
triangular prism 5 9 6
square-based pyramid 5 8 5
cylinder 2 plane faces + 1 curved surface 2 circular boundaries 0
cone 1 plane face + 1 curved surface 1 circular boundary 1

For a prism with an nn-sided end face: faces =n+2=n+2, edges =3n=3n, vertices =2n=2n. Trace systematically so hidden dashed edges are included.

Do not count a drawn diagonal, construction line or curved outline twice; perspective drawings can hide genuine edges but do not create new ones.

Find surface areas from faces and nets

Total surface area is the sum of the areas of every exposed face. A net or face inventory turns the 3D solid into separate triangles and rectangles that can be checked.

Step Action
1 identify the congruent end faces
2 list every lateral rectangle with its two dimensions
3 calculate each face area and group equal faces
4 omit only faces explicitly open, joined or unpainted

For a right prism, lateral area equals perimeter of cross-section ×\times prism length; then add the two end areas when both are exposed.

Volume units are cubic, but surface area units are square. A hidden face still contributes unless it is joined internally or the question excludes it.

Find the surface area of a cylinder

Unrolling a cylinder gives a rectangle of width 2πr2\pi r and height hh. Its curved area is 2πrh2\pi rh, so total surface area is 2πrh+2πr22\pi rh+2\pi r^2.

Cylinder Surface area
closed 2πrh+2πr22\pi rh+2\pi r^2
open at one end 2πrh+πr22\pi rh+\pi r^2
curved surface only 2πrh2\pi rh

Confirm whether the given circular measure is radius or diameter, find any missing height from other data if needed, and include exactly the exposed circular ends.

The circle formula πr2\pi r^2 is used for each end; 2πr2\pi r is a length and becomes an area only after multiplication by height.

Find volumes of prisms and cylinders

Every prism has volume V=(cross-sectional area)×(perpendicular length)V=(\text{cross-sectional area})\times(\text{perpendicular length}). Thus a cuboid has V=lwhV=lwh and a cylinder has V=πr2hV=\pi r^2h.

Step Decision
1 identify the constant end cross-section
2 calculate its area in square units
3 multiply by the perpendicular prism length
4 convert units before comparing capacity, cost or count

For packing, volume alone gives an upper bound; whole boxes must also fit by their dimensions. For filling, divide the required volume by a rate or container capacity and round according to context.

Do not multiply by a sloping edge unless it is the perpendicular distance through which the cross-section is repeated.

Convert metric volumes and litres

A linear conversion factor is cubed for volume. Since 1 m=100 cm1\text{ m}=100\text{ cm}, 1 m3=1003 cm3=1,000,000 cm31\text{ m}^3=100^3\text{ cm}^3=1{,}000{,}000\text{ cm}^3.

Relationship Equivalent volume
1 m31\text{ m}^3 1,000,000 cm31{,}000{,}000\text{ cm}^3
1 litre1\text{ litre} 1000 cm31000\text{ cm}^3
1 m31\text{ m}^3 1000 litres1000\text{ litres}

Write the one-dimensional relationship, cube its factor for cubic units, then multiply toward smaller units or divide toward larger units. Use the litre bridge only after units are compatible.

Multiplying by 100100 converts a length, not a volume; multiplying by 1002100^2 converts an area, not a volume.

Find sphere and right-cone measures

For a sphere, surface area is 4πr24\pi r^2 and volume is 43πr3\frac43\pi r^3. For a right circular cone, volume is 13πr2h\frac13\pi r^2h, curved area is πrl\pi rl, and total area is πrl+πr2\pi rl+\pi r^2.

Shape feature Relationship
right cone l2=r2+h2l^2=r^2+h^2
hemisphere volume 23πr3\frac23\pi r^3
hemisphere curved area 2πr22\pi r^2
solid hemisphere total area 3πr23\pi r^2 including its base

For joined solids, add volumes but count only external surfaces. For a hollow or removed part, subtract its volume or exposed area. Similar cones scale lengths by kk, areas by k2k^2 and volumes by k3k^3.

Cone surface area uses slant height ll, while cone volume uses perpendicular height hh. A joined circular face is internal and must not be counted in external surface area.