4.8 Trigonometry and Pythagoras’ theorem

Syllabus
2017
Topic
4.8
Level
Foundation

Use Pythagoras' theorem in two dimensions

In a right-angled triangle, the square of the hypotenuse equals the sum of the squares of the other two sides: c2=a2+b2c^2=a^2+b^2. The hypotenuse cc is always opposite the right angle.

Unknown Rearrangement
hypotenuse c=a2+b2c=\sqrt{a^2+b^2}
shorter side a=c2b2a=\sqrt{c^2-b^2}

Mark the right angle, identify the hypotenuse, substitute lengths with units, then take the positive square root. In a compound shape, form one right triangle at a time and carry the unrounded result forward.

Do not add the squares when the unknown is a shorter side, and do not use Pythagoras unless the triangle is right-angled.

Use trigonometry in right-angled triangles

Relative to an acute angle θ\theta, sinθ=OH\sin\theta=\frac{O}{H}, cosθ=AH\cos\theta=\frac{A}{H} and tanθ=OA\tan\theta=\frac{O}{A}. Label opposite, adjacent and hypotenuse before choosing a ratio.

Known and wanted sides Ratio
opposite and hypotenuse sine
adjacent and hypotenuse cosine
opposite and adjacent tangent

For a length, rearrange the chosen ratio. For an angle, use the matching inverse function, such as θ=tan1(O/A)\theta=\tan^{-1}(O/A). Keep the calculator in degree mode and round only the final answer.

Adjacent means the non-hypotenuse side beside the chosen angle; its identity changes when the reference angle changes.

Model two-dimensional trigonometry and bearings

Translate the context into a labelled 2D diagram. Bearings are measured clockwise from north and written with three figures, so first convert the bearing information into the interior angle needed by the right triangle.

Step Decision
1 draw north lines and known distances
2 use parallel north lines, right angles or angle sums to find the working angle
3 select Pythagoras or SOHCAHTOA
4 convert the result back to a clockwise three-figure bearing

A bearing such as 142142^\circ describes a direction from north; an interior triangle angle such as 3838^\circ is not automatically the final bearing.

This Foundation objective uses right-triangle decomposition. The sine rule and cosine rule for non-right triangles are taught separately in 4.8.HC.

Use trigonometric ratios for obtuse angles

For 90<θ<18090^\circ<\theta<180^\circ, the reference angle is 180θ180^\circ-\theta. Sine stays positive, while cosine and tangent are negative.

Ratio Obtuse-angle relationship
sine sinθ=sin(180θ)\sin\theta=\sin(180^\circ-\theta)
cosine cosθ=cos(180θ)\cos\theta=-\cos(180^\circ-\theta)
tangent tanθ=tan(180θ)\tan\theta=-\tan(180^\circ-\theta)

Sketch the angle in the second quadrant, find its acute reference angle, apply the correct sign, and check the calculator is in degree mode.

An inverse-sine display gives a principal acute value; contextual or stated obtuse conditions may require the supplementary angle 180θ180^\circ-\theta.

Solve angles of elevation and depression

Angles of elevation and depression are measured from a horizontal line. Parallel horizontals make the angle of depression equal to the corresponding angle of elevation.

Information Triangle quantity
two object heights often subtract to obtain vertical separation
horizontal ground distance adjacent side
line of sight hypotenuse

Draw a horizontal through the observer, label the vertical difference and horizontal distance, then use the right-triangle ratio that connects the known sides to the required angle or length.

Do not measure the angle from the vertical, and do not use a full height when the line of sight joins points already above the ground.

Use the sine rule and cosine rule

For any triangle, asinA=bsinB=csinC\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C} and a2=b2+c22bccosAa^2=b^2+c^2-2bc\cos A, where each side is paired with its opposite angle.

Given Usually choose
an opposite side-angle pair sine rule
three sides, or two sides and included angle cosine rule

Label opposite pairs, choose a form with one unknown, substitute without premature rounding, and test the result against the largest-side/largest-angle relationship. For the sine-rule ambiguous case, check whether the supplementary angle also satisfies the data and angle sum.

The cosine rule uses the angle included between the two named sides. An inverse-sine answer alone can miss a valid obtuse solution.

Use Pythagoras' theorem in three dimensions

A 3D distance can be built from right triangles on perpendicular planes. In a cuboid, the space diagonal satisfies d2=l2+w2+h2d^2=l^2+w^2+h^2.

Stage Construction
face find a diagonal from two perpendicular edges
space combine that diagonal with the perpendicular third direction

Identify the two endpoints, draw or name a helpful face projection, prove the relevant angle is 9090^\circ, then apply Pythagoras once or twice. Keep surds exact when requested.

Do not combine three lengths unless they represent mutually perpendicular directions; a sloping edge may already include more than one direction.

Find triangle area using sine

The area of a triangle with sides aa and bb enclosing angle CC is A=12absinCA=\frac12ab\sin C. The angle must be between the two chosen sides.

Required quantity Rearrangement
area A=12absinCA=\frac12ab\sin C
side aa a=2AbsinCa=\frac{2A}{b\sin C}
included angle C=sin1(2A/ab)C=\sin^{-1}(2A/ab), then check alternatives

Split compound shapes into triangles, calculate each contribution, and add or subtract as the geometry requires. Preserve full precision until the final stated accuracy.

Do not use a non-included angle with the two selected sides, and remember to double only when symmetry actually creates two congruent triangles.

Use trigonometry in three dimensions

The angle between a line and a plane is the angle between the line and its perpendicular projection onto that plane. This creates a right triangle containing the line, its projection and the perpendicular height.

Step Action
1 identify where the line meets the plane
2 find the line's projection in the plane, often with Pythagoras
3 use the projection and perpendicular height in a right triangle
4 state the required line-plane angle, not a different 3D angle

A useful check is that the projection is shorter than the sloping line and the chosen angle lies between 00^\circ and 9090^\circ.

The angle between a line and a plane is not the angle between two planes or between the line and an arbitrary edge in the plane.