(c) Alkanes

Syllabus
2024
Topic
Level

Learning objectives

Use the alkane general formula

Alkanes form a homologous series with the general formula CXnHX2n+2\ce{C_nH_{2n+2}}, where nn is a positive whole number equal to the number of carbon atoms.

nn Name Molecular formula
1 methane CHX4\ce{CH4}
2 ethane CX2HX6\ce{C2H6}
3 propane CX3HX8\ce{C3H8}
4 butane CX4HX10\ce{C4H10}
5 pentane CX5HX12\ce{C5H12}

To test a proposed alkane formula, count its carbon atoms, substitute that value for nn, and check whether the hydrogen count is 2n+22n+2. For example, n=6n=6 gives CX6HX14\ce{C6H14}.

The general formula describes molecular formulae for open-chain alkanes. Do not simplify CX2HX6\ce{C2H6} to the empirical formula CHX3\ce{CH3}, and do not use the alkene formula CXnHX2n\ce{C_nH_{2n}}.

Explain why alkanes are saturated hydrocarbons

An alkane is a saturated hydrocarbon: it contains carbon and hydrogen only, and every bond between carbon atoms is a single covalent bond.

Classification Evidence in an alkane
hydrocarbon the molecule contains only carbon and hydrogen atoms
saturated there are no carbon–carbon double or triple bonds; the carbon framework carries the maximum number of hydrogens for that open chain

Because an alkane has no C=C\ce{C=C} bond to open, it does not undergo the addition reactions characteristic of alkenes. Its reaction with a halogen is substitution instead.

Saturated does not mean that every carbon atom is bonded to four hydrogen atoms. Carbon makes four bonds in total; in ethane, for example, each carbon also bonds to the other carbon.

Draw and name alkanes up to five carbons

A structural formula shows how atoms are grouped along the carbon chain; a displayed formula shows every atom and every covalent bond.

Carbon atoms Unbranched name Molecular formula Condensed structural formula
1 methane CHX4\ce{CH4} CHX4\ce{CH4}
2 ethane CX2HX6\ce{C2H6} CHX3CHX3\ce{CH3CH3}
3 propane CX3HX8\ce{C3H8} CHX3CHX2CHX3\ce{CH3CH2CH3}
4 butane CX4HX10\ce{C4H10} CHX3CHX2CHX2CHX3\ce{CH3CH2CH2CH3}
5 pentane CX5HX12\ce{C5H12} CHX3CHX2CHX2CHX2CHX3\ce{CH3CH2CH2CH2CH3}

For a displayed formula, first join the required carbon skeleton using single bonds. Then add hydrogen atoms until every carbon has four bonds and every hydrogen has one. Count the atoms at the end to confirm the molecular formula.

Structural isomers have the same molecular formula but different carbon connectivity. CX4HX10\ce{C4H10} has straight-chain butane and branched methylpropane; CX5HX12\ce{C5H12} has pentane, 2-methylbutane and 2,2-dimethylpropane.

Rotating or bending the same chain does not create a new isomer. Compare which carbon atoms are connected, and use methane, ethane, propane, butane and pentane for the required unbranched-chain names.

Describe mono-substitution of alkanes by halogens

In ultraviolet radiation, an alkane reacts with a halogen by substitution: one halogen atom replaces one hydrogen atom in the alkane.

Reactants Required condition Products after one substitution
alkane + chlorine ultraviolet radiation chloroalkane + hydrogen chloride
alkane + bromine ultraviolet radiation bromoalkane + hydrogen bromide

\ce{CH4 + Cl2 ->[UV] CH3Cl + HCl}

\ce{C2H6 + Br2 ->[UV] C2H5Br + HBr}

Keep the carbon skeleton unchanged, replace exactly one H by Cl or Br, and use the other halogen atom to form HCl\ce{HCl} or HBr\ce{HBr}. Check that every atom is conserved.

For this specification, stop after mono-substitution and state ultraviolet radiation. Further substitutions can occur chemically, but they are outside 4.22; reaction mechanisms are also not required. Do not call this addition.