(g) Acids, bases and salt preparations
- Syllabus
- 2024
- Topic
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- Level
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An ionic compound is soluble if enough of it dissolves in water to form an aqueous solution. Apply the cation rule first when it gives an unconditional result, then check the anion and its exceptions.
| Compound group | General rule | Exceptions or limits |
|---|---|---|
| sodium, potassium and ammonium compounds | soluble | none in the required rules |
| nitrates | soluble | none in the required rules |
| chlorides | soluble | silver chloride and lead(II) chloride are insoluble |
| sulfates | soluble | barium, calcium and lead(II) sulfates are insoluble |
| carbonates | insoluble | sodium, potassium and ammonium carbonates are soluble |
| hydroxides | insoluble | sodium and potassium hydroxides are soluble; calcium hydroxide is slightly soluble |
Potassium carbonate is soluble because all common potassium compounds are soluble. Barium sulfate is insoluble because barium is a sulfate exception, so mixing solutions that supply BaX2+ and SOX4X2− forms a precipitate.
Do not apply only the broad anion rule and ignore an exception. 'Slightly soluble' is the specified classification for calcium hydroxide; it is not grouped with fully soluble sodium and potassium hydroxides.
An acid–base reaction involves transfer of a proton, HX+, from one particle to another. The proton is not released and left unaccounted for: one species loses it as another gains it.
\ce{H+(aq) + OH-(aq) -> H2O(l)}
In neutralisation, the acid supplies HX+ and the hydroxide ion gains that proton to become HX2O. Tracking the same hydrogen and its positive charge shows exactly what has transferred.
Proton transfer is not electron transfer. A proton is HX+; oxidation and reduction instead track electrons, so an acid–base reaction is not automatically redox.
An acid is a proton donor and a base is a proton acceptor. Identify each role by comparing a species before and after the reaction.
\ce{HCl + NH3 -> NH4+ + Cl-}
| Species | Change | Role |
|---|---|---|
| HCl | loses HX+ and becomes ClX− | acid: proton donor |
| NHX3 | gains HX+ and becomes NHX4X+ | base: proton acceptor |
Do not decide from a formula alone when a reaction is supplied: follow the proton. The acid loses HX+; the base does not donate it and does not need to contain OHX−.
Hydrochloric, sulfuric and nitric acids form different salt families: chlorides, sulfates and nitrates. The other products depend on whether the acid reacts with a metal, a base or a metal carbonate.
| Reactants | Products | Example |
|---|---|---|
| acid + metal | salt + hydrogen | 2HCl+MgMgClX2+HX2 |
| acid + base | salt + water | HX2SOX4+CuOCuSOX4+HX2O |
| acid + metal carbonate | salt + water + carbon dioxide | 2HNOX3+CaCOX3Ca(NOX3)X2+HX2O+COX2 |
Metal reactions usually show hydrogen bubbles as the metal disappears. Carbonates effervesce because carbon dioxide escapes. With a solid base such as copper(II) oxide, the solid disappears as a salt solution forms when the base is not in excess.
Reactions between nitric acid and metals are explicitly excluded here, so do not apply the salt-plus-hydrogen pattern to them. Preserve formulas, coefficients and the acid-derived salt name.
A base neutralises an acid by accepting protons. Metal oxides, metal hydroxides and ammonia can act as bases; an alkali is specifically a base that is soluble in water.
| Substance | Acts as a base? | Alkali? | Reason |
|---|---|---|---|
| copper(II) oxide | yes | no | neutralises acid but is insoluble in water |
| sodium hydroxide | yes | yes | dissolves in water and supplies OHX− |
| calcium hydroxide | yes | slightly soluble alkali | its limited solubility still gives an alkaline solution |
| ammonia | yes | aqueous ammonia is alkaline | accepts HX+ and produces an alkaline solution in water |
All alkalis are bases because they neutralise acids, but not all bases are alkalis because many bases are insoluble. Solubility—not whether the name contains 'hydroxide'—controls the alkali label.
A metal oxide can be a base without containing OHX− in its formula, and ammonia can be a base without being a metal hydroxide. Do not use 'base' and 'alkali' as exact synonyms.
Use an excess insoluble oxide, hydroxide or carbonate—or a suitable metal with hydrochloric or sulfuric acid—to consume all the acid, then remove the unused solid before crystallising the soluble salt.
| Stage | Purpose |
|---|---|
| 1. Warm dilute acid gently. | increases reaction rate without boiling away acid |
| 2. Add the insoluble solid in small portions while stirring until some remains. | excess solid shows all acid has reacted |
| 3. Filter. | removes the unreacted excess solid; the salt is in the filtrate |
| 4. Heat the filtrate until near saturation. | evaporates some water without drying the salt completely |
| 5. Cool to crystallise, filter the crystals and dry them. | obtains a pure, dry sample |
Choose reactants that form the required soluble salt. For magnesium nitrate, warm nitric acid with excess magnesium oxide, then filter and crystallise the magnesium nitrate solution.
Do not evaporate the solution to dryness when hydrated crystals are required. Filtering before crystallisation is essential: otherwise excess reactant contaminates the crystals.
An acid and an alkali are both soluble, so excess reactant cannot be removed by filtration. First use a titration to find the exact reacting volumes, then remake the salt solution without indicator.
| Stage | Action |
|---|---|
| 1 | Pipette a fixed alkali volume into a conical flask, add a suitable indicator and titrate with acid to the end-point. |
| 2 | Repeat to obtain a reliable reacting volume. |
| 3 | Mix the same measured acid and alkali volumes again, but add no indicator. |
| 4 | Heat the pure salt solution to near saturation, then leave it to cool and crystallise. |
| 5 | Filter the crystals, rinse with a little cold distilled water and dry them. |
Sulfuric acid and sodium hydroxide form sodium sulfate solution: HX2SOX4+2NaOHNaX2SOX4+2HX2O. The indicator-free repeat prevents coloured indicator contaminating the crystals.
Do not add excess acid or alkali: both remain dissolved and cannot be filtered off. The first titration finds the proportions; it is not normally the solution crystallised because it contains indicator.
Prepare an insoluble salt by mixing two soluble salt solutions whose ions combine to form the required precipitate.
| Stage | Action and reason |
|---|---|
| 1 | Select two soluble compounds that supply the required cation and anion; dissolve them separately if starting from solids. |
| 2 | Mix and stir the solutions so the insoluble salt precipitates. |
| 3 | Filter to collect the precipitate as the residue. |
| 4 | Wash the residue with distilled water to remove soluble impurities. |
| 5 | Dry between filter papers, in a warm oven or in a desiccator. |
\ce{BaCl2(aq) + Na2SO4(aq) -> BaSO4(s) + 2NaCl(aq)}
The desired insoluble salt is the filter residue, not the filtrate. Do not use evaporation or crystallisation: those methods recover a dissolved soluble salt, whereas the precipitate has already formed as a solid.
Prepare hydrated copper(II) sulfate by reacting warm dilute sulfuric acid with excess insoluble copper(II) oxide, then crystallising the blue solution.
\ce{CuO(s) + H2SO4(aq) -> CuSO4(aq) + H2O(l)}
| Stage | Observation or purpose |
|---|---|
| 1 | Warm dilute sulfuric acid in a beaker; do not boil. |
| 2 | Add black copper(II) oxide a little at a time with stirring until black solid remains. |
| 3 | Filter off excess CuO; collect the blue copper(II) sulfate filtrate. |
| 4 | Heat gently until a cooled drop forms crystals, then leave the solution to cool. |
| 5 | Filter the blue crystals, rinse with a little cold distilled water and dry between filter papers. |
Excess copper(II) oxide removes all acid and is later filtered off. Do not strongly heat the final crystals or evaporate to dryness, because the target is hydrated copper(II) sulfate.
Lead(II) sulfate is insoluble, so prepare it as a precipitate by mixing two soluble solutions that supply PbX2+ and SOX4X2− ions.
\ce{Pb(NO3)2(aq) + Na2SO4(aq) -> PbSO4(s) + 2NaNO3(aq)}
| Stage | Action |
|---|---|
| 1 | Mix measured lead(II) nitrate and sodium sulfate solutions and stir to complete precipitation. |
| 2 | Filter the mixture; retain the solid lead(II) sulfate residue. |
| 3 | Wash the residue with distilled water to remove soluble sodium nitrate and excess ions. |
| 4 | Dry the solid between filter papers or in a warm oven. |
Lead compounds are toxic: wear eye protection and gloves, avoid skin contact and dust, use small quantities, wash hands and place all lead-containing residues and liquids in the designated hazardous-waste container.