E2.1 Introduction to algebra

Syllabus
0580–2028–2029
Topic
E2.1
Level
Extended

Use letters to represent general numbers

A letter can stand for a number whose value is not fixed yet or may change. This lets one algebraic expression describe every value that fits the same relationship.

Relationship Algebra Meaning
five copies of a number nn 5n5n 5×n5\times n
three more than nn n+3n+3 add 3 to the value of nn
£48 shared equally among xx people 48/x48/x each share when x0x\ne0
a number pp decreased by 7 p7p-7 subtract 7 from the value of pp

If one notebook costs £pp, then five notebooks cost £5p5p. The same expression works whether p=2p=2, p=3.50p=3.50 or another allowed price. The letter represents the number; it is not an abbreviation for the object.

Within one expression, every occurrence of the same letter has the same value. Different letters represent quantities independently unless the context states a relationship between them.

5n5n means 5×n5\times n, not 5+n5+n and not the two-digit number “5n”. Keep the operation stated by the relationship: “three more” gives n+3n+3, while “three times” gives 3n3n.

Substitute values into expressions and formulas

Substitution means replacing each letter with its given numerical value while keeping every operation in the original expression or formula.

Use this order: (1) write the original expression; (2) replace every letter with its value, putting negative values in brackets; (3) evaluate powers and brackets first; (4) multiply or divide; (5) add or subtract; (6) check that every occurrence was replaced.

F=2a2+3b,a=3, b=4F=2a^2+3b,\qquad a=-3,\ b=4

Substitute before calculating: F=2(3)2+3(4)F=2(-3)^2+3(4). Then (3)2=9(-3)^2=9, so F=2(9)+12=30F=2(9)+12=30. The brackets ensure the square applies to the whole negative value.

A formula may contain several letters. For s=12(u+v)ts=\frac12(u+v)t with u=20u=20, v=30v=30 and t=7t=7, substitution gives s=12(20+30)(7)=175s=\frac12(20+30)(7)=175. Keep the grouping shown by the formula.

Do not change signs or operations while substituting. In particular, (3)2=9(-3)^2=9 but 32=9-3^2=-9 because the exponent applies before the leading minus when there are no brackets.