EduNinja

[Maximum number: 5]

Figure for Question 1 — CAIE IGCSE Mathematics Core

NOT TO SCALE

An isosceles triangle has base 12 cm and sides 16 cm. Find the area of this triangle.
$\mathrm{cm}^2$

The height is
$\sqrt{16^2-\left(\frac{12}{2}\right)^2}=\sqrt{220}.$
Hence the area is
$\frac12\times12\times\sqrt{220}=6\sqrt{220}=89.0\ \mathrm{cm^2}\ \text{(approximately)}.$

[Maximum number: 2]

Figure for Question 2 — CAIE IGCSE Mathematics Core

The diagram shows a field PQRS.
$PQ=98\,\mathrm{m}$ , $QR=67\,\mathrm{m}$ and angle $PQR=90^\circ$ .
There is a straight path from P to R.
Calculate the length of this path.
m

119 or 118.7...

M1 for $98^2+67^2$ or better

[Maximum number: 3]

Figure for Question 3 — CAIE IGCSE Mathematics Core

The diagram shows a circle, centre O, with diameter PQ. R is a point on the circumference.

Calculate the length of PQ.

P Q=

cm [3]

7.31 or 7.310 to 7.311

M2 for $\frac{6.2}{\cos32^\circ}$ oe.
M1 for $\frac{6.2}{PQ}$ oe.

CAIE IGCSE Mathematics Core C6.1 Pythagoras Theorem Topic Practice

Question 1

Question 2

Question 3