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IB Maths AA SL/Question Bank/5.1 Calculus - SL content

IB Maths AA SL5.1 Calculus - SL contentQuestion Bank

SL251 questions10 previewsSyllabus linked
[Maximum number: 5]

Let f(x)=lnx5xf(x)=\ln x-5 x, for x>0.

(a)

Find f(x)f^{\prime}(x).

[ 2 ]
(b)

Find f(x)f^{\prime \prime}(x).

[ 1 ]
(c)

Solve f(x)=f(x)f^{\prime}(x)=f^{\prime \prime}(x).

[ 2 ]
[Maximum number: 2]

Consider the function f(x)=x2+x+50x,x0f(x)=x^{2}+x+\frac{50}{x}, x \neq 0.

(a)

Find the coordinates of A.

[ 2 ]
(a)

Find (6x+7)dx\int(6 x+7) \mathrm{d} x.

[ 3 ]
(b)

Given f(x)=6x+7f^{\prime}(x)=6 x+7 and f(1.2)=7.32, find f(x).

[ 3 ]
[Maximum number: 7]

Consider the function defined by f(x)=x28xf(x)=x^{2}-8 x. The graph of f passes through the point A(3,-15).

(a)
(i)

Find the gradient of the tangent to the graph of f at the point A .

[ 3 ]
(b)

Write down the equation of the normal to the graph of f at point A .

The normal to the graph of f at point A intersects the graph of f again at a second point B .

[ 1 ]
(c)

Find the coordinates of B.

[ 3 ]
[Maximum number: 3]

Consider the function f(x)=(x1)2xf(x)=\frac{(x-1)^{2}}{x}, where xR,x0x \in \mathbb{R}, x \neq 0.

(a)

Hence, find f(x)dx\int f(x) \mathrm{d} x.

[ 3 ]
[Maximum number: 4]

Consider the function f(x)=x3+5x28f(x)=x^{3}+5 x^{2}-8, where xRx \in \mathbb{R}.

(a)

Find f(1)f^{\prime}(1).

[ 2 ]
(b)

Find the equation of the tangent to the graph of f at x=1.

[ 2 ]
[Maximum number: 2]

Let f(x)=6x24exf(x)=\frac{6 x^{2}-4}{\mathrm{e}^{x}}, for 0x70 \leq x \leq 7.

(a)

The graph of f has a maximum at the point A . Write down the coordinates of A .

[ 2 ]
[Maximum number: 6]

Let f(x)=6x23xf(x)=6 x^{2}-3 x. The graph of f is shown in the following diagram.

Question image
(a)

Find (6x23x)dx\int\left(6 x^{2}-3 x\right) \mathrm{d} x.

[ 2 ]
(b)

Find the area of the region enclosed by the graph of f, the x-axis and the lines x=1 and x=2.

[ 4 ]
[Maximum number: 5]

The derivative of a function g is given by g(x)=3x2+5exg^{\prime}(x)=3 x^{2}+5 \mathrm{e}^{x}, where xRx \in \mathbb{R}. The graph of g passes through the point (0,4). Find g(x).

(a)

Hence, find the value of 19(3x5x)dx\int_{1}^{9}\left(\frac{3 \sqrt{x}-5}{\sqrt{x}}\right) \mathrm{d} x.

[ 4 ]
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