AHL 3.16 (HL)—Vector product
- Syllabus
- First assessment 2021
- Objective
- —
- Level
- HL
The vector product creates a perpendicular direction.
a×b is perpendicular to both vectors and has magnitude |a||b|sinθ, making it useful for normals and areas.
(1,0,0)×(0,2,0)=(0,0,2), whose magnitude 2 is the area of the rectangle spanned by the vectors.
Use the determinant pattern, then apply the right-hand rule to interpret orientation and check the magnitude.
Reversing the order changes the sign: a×b=−(b×a); parallel vectors give the zero vector.
For a=(a1,a2,a3) and b=(b1,b2,b3), compute a×b=(a2b3−a3b2, a3b1−a1b3, a1b2−a2b1). Its magnitude is the area of the spanned parallelogram, so the corresponding triangle area is 21∣a×b∣. The zero vector occurs for non-zero parallel inputs, while order controls the normal's direction.