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AP Statistics 3.11.A Interpreting Two-Proportion Intervals

Practise interpreting confidence intervals for differences in population proportions by preserving the subtraction order, confidence level, endpoints, and context.

Syllabus
Effective Fall 2026
Course
AP Statistics

Exam points

  • State the confidence level, interval endpoints, subtraction order, and two populations in context.
  • Allow a negative interval for a difference in proportions and interpret its direction correctly.

3.11.A—Interpret a confidence interval in context for the difference between two population proportions question 1

[Maximum number: 1]

In a simple random sample (SRS) of 625 families who do not live near any chemical plant, 10 had children with leukemia. In an SRS of 412 families living near chemical plants, 15 had children with leukemia. A 90\% confidence interval of the difference in proportions is reported to be 0.0204±0.0173-0.0204 \pm 0.0173. What is a proper conclusion?

A

The interval is invalid because probabilities cannot be negative.

B

Families living near chemical plants are approximately 2.04\% more likely to have children with leukemia than families who do not live near any chemical plant.

C

Ninety percent of families living near chemical plants are approximately 2.04\% more likely to have children with leukemia than families who do not live near any chemical plant.

D

We are 90%90 \% confident that the difference in proportions between families who do not live near any chemical plant having children with leukemia and families who live near chemical plants having children with leukemia is between -0.0377 and -0.0031.

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